Answer:
Part a: The rate of the equation for 1st order reaction is given as ![Rate=k[H_2O_2]](https://tex.z-dn.net/?f=Rate%3Dk%5BH_2O_2%5D)
Part b: The integrated Rate Law is given as ![[H_2O_2]=[H_2O_2]_0 e^{-kt}](https://tex.z-dn.net/?f=%5BH_2O_2%5D%3D%5BH_2O_2%5D_0%20e%5E%7B-kt%7D)
Part c: The value of rate constant is 
Part d: Concentration after 4000 s is 0.043 M.
Explanation:
By plotting the relation between the natural log of concentration of
, the graph forms a straight line as indicated in the figure attached. This indicates that the reaction is of 1st order.
Part a
Rate Law
The rate of the equation for 1st order reaction is given as
![Rate=k[H_2O_2]](https://tex.z-dn.net/?f=Rate%3Dk%5BH_2O_2%5D)
Part b
Integrated Rate Law
The integrated Rate Law is given as
![[H_2O_2]=[H_2O_2]_0 e^{-kt}](https://tex.z-dn.net/?f=%5BH_2O_2%5D%3D%5BH_2O_2%5D_0%20e%5E%7B-kt%7D)
Part c
Value of the Rate Constant
Value of the rate constant is given by using the relation between 1st two observations i.e.
t1=0, M1=1.00
t2=120 s , M2=0.91
So k is calculated as

The value of rate constant is 
Part d
Concentration after 4000 s is given as

Concentration after 4000 s is 0.043 M.
<span>When a strontium atom loses two electrons, it becomes a(n) cation with a charge of 2+.
when any neutral atom loses an electron it becomes cation that is positively charged ions and an ion gets the charge according to the number of electrons loses. And if an atom gains an electron it becomes anion that is negatively charged ions.</span>
2 × (atomic mass of Ag) + (atomic mass of Cl (
Answer:
To find the ionic charge of an element you'll need to consult your Periodic Table. On the Periodic Table metals (found on the left of the table) will be positive. Non-metals (found on the right) will be negative.
Explanation: