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Andrei [34K]
3 years ago
12

Graph the piecewise-defined function

Mathematics
2 answers:
astraxan [27]3 years ago
3 0

Start by graphing y = |x|. Its vertex is at (0,0), and the graph opens up.

Now translate the entire graph 4 units up. The new vertex will be at (0,4). Draw an empty circle around this point.

Darken the graph of y = |x|+4 ONLY for the part which is left of the y-axis.

Now plot a dark dot at (0,4). Draw a dark, horiz. line from that dot to the right.

That's it!

STatiana [176]3 years ago
3 0
<h2>Answer with explanation:</h2>

The function f(x) is given by:

f(x)=  |x|+4, if  x<0

 and    4 ,  if x ≤ 0.

  • for x<0

The graph of the function is a strictly decreasing continuous graph i.e. a line with a slope as: -1.

Since, the function f(x) for x<0 is given by:

f(x)= -x+4

also at x=0-    f(x)=4

  • Also , for x≥0 the graph of the function is a straight line parallel to the x-axis.

Also, the left hand limit at x=0 is equal to the right hand limit at x=0 is equal to the function's value at x=0.

Hence, the graph of the function is continuous for all the real values.

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The sum of the digits of a two-digit number is 11. When the digits are reversed, the new number is 27 more than the original num
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Answer: 47

Step-by-step explanation: To solve this problem, let's use <em>t</em> to represent our tens digit and <em>u</em> to represent our units digit so that the value of our number can be represented as 10<em>t</em> + <em>u</em>.

If we represent the value of our number as 10<em>t</em> + <em>u</em>, the value of the number with the digits reversed can be represented as 10<em>u</em> + <em>t</em>.

Since the first sentence states that the sum of the digits of a two-digit number is 11, that's <em>t </em>+<em> u</em> = 11.

Reading through our second sentence, when the digits are reversed, the new number is 27 more than the original number, that's 10<em>u</em> + <em>t</em> "is" which means equals 27 more than the original number that's 10<em>t </em>+ <em>u</em> + 27.

So 10<em>t</em> + <em>u</em> = 10<em>t</em> + <em>u</em> + 27.

Before solving this system however, let's rearrange our second equation so that the t's and u's are on the same side by subtracting 10<em>t</em> and <em>u</em> from both sides to get 9<em>u</em> - 9<em>t</em> = 27 and when we rewrite our first equation above it, instead of writing it as <em>t</em> + <em>u</em> = 11, let's write it as <em>t</em> + <em>u</em> = 11 so that our u's and t's will match up in the system.

To solve this system, let's use addition so multiply the top equation by 9 to get 9<em>u </em>+ 9<em>t</em> = 99 and 9<em>u</em> - 9<em>t</em> = 27 so that when we add the equations together the t's cancel and we get 18<em>u</em> = 126. Dividing both sided by 18, <em>u </em>= 7.

To find <em>t</em>, plug 7 back in for <em>u</em> in our first equation to get <em>t</em> + 7 = 11. Subtract 7 from both sides and <em>t</em> = 4.

Since our tens digit is 4 and our units is 7, our number must be 47.

I have also attached my work on a whiteboard.

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