Question

Use the quadratic formula to solve this equation: x2 = -3x + 40 x=−b±b2−4ac√2a

Answer 1

The solution is x = 5 and x= -8

Step-by-step explanation:

Given equation is:

$x^2=-3x+40$

Converting in standard form

$x^2+3x-40 = 0$

The standard form of quadratic equation is:

$ax^2+bx+c = 0$

Here

a = 1

b = 3

c = -40

Quadratic formula is given as:

$x = \frac{-b+\sqrt{b^2-4ac}}{2a}\ \ \ \ , \ \ \ \ x = \frac{-b-\sqrt{b^2-4ac}}{2a}$

Putting the values of a, b and c

$x = \frac{-3+\sqrt{(3)^2-4(1)(-40)}}{2(1)}\ \ \ \ , \ \ \ \ x = \frac{-3-\sqrt{(3)^2-4(1)(-40)}}{2(1)}\\x = \frac{-3+\sqrt{9+160}}{2}\ \ \ \ \ \ \ \ \ \ \ \ \ \ , \ \ \ \ x = \frac{-3-\sqrt{9+160}}{2}\\x = \frac{-3+\sqrt{169}}{2}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ , \ \ \ \ x = \frac{-3-\sqrt{169}}{2}\\x = \frac{-3+13}{2}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ , \ \ \ \ x = \frac{-3-13}{2}\\x = \frac{10}{2}\ \ \ \ \ \ \ \ \ \ \ \ \ , \ \ \ \ x = \frac{-16}{2}\\x = 5\ \ \ \ \ And \ \ \ \ \ \ x = -8$

Hence,

The solution is x = 5 and x= -8

Keywords: Quadratic equation, variables

Learn more about quadratic equation at:

• brainly.com/question/10717746
• brainly.com/question/10736268

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