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3 years ago

Who thinks the wap song is weird

Mathematics

2 answers:

Anna35 [415]3 years ago

8 0

Answer:

It a bit vulgar, but Cardi B is still a good artsist

Yanka [14]3 years ago

3 0

Answer:

me-_-

Step-by-step explanation:

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wlad13 [49]

Answer:

Step-by-step explanation:

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3 years ago

Yet another variation: A better packet switched network employs the concept of acknowledgment. When the end user’s device receiv

hram777 [196]

Answer:

P(N = n) = $(1-P)^{n-1} \times P$

Step-by-step explanation:

to find out

Find the PMF PN (n)

solution

PN (n)

here N is random variable

and n is the number of times

so here N random variable is denote by the same package that is N (P)

so here

probability of N is

P(N ) = Ф ( N = n) .................. 1

here n is = 1, 2,3, 4,...................... and so on

so that here P(N = n) will be

P(N = n) = $(1-P)^{n-1} \times P$

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2 years ago

Angle PQRPQR and angle TQVTQV are vertical angles. The measures of the two angles have a sum of 100^{\circ}100

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3 years ago

Read 2 more answers

Calculate the shaded areas for c and d

KiRa [710]

C)
Area of full triangle
1/2(8)(6)=24cm^2
Area of non shaded triangle
1/2(4)(3)=6cm^2
Area of full minus area of small triangle
24-6=18cm^2

D)
Area of Big rectangle
(4)(12)=48
Area of non shaded triangle
1/2(9)(4)=18
Area of Big rectangle minus non shaded triangle
48-18=30cm^2

5 0

2 years ago

Suppose that X has a Poisson distribution with a mean of 64. Approximate the following probabilities. Round the answers to 4 dec

o-na [289]

Answer:

(a) The probability of the event (X > 84) is 0.007.

(b) The probability of the event (X < 64) is 0.483.

Step-by-step explanation:

The random variable X follows a Poisson distribution with parameter λ = 64.

The probability mass function of a Poisson distribution is:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0, 1, 2, ...$

(a)

Compute the probability of the event (X > 84) as follows:

P (X > 84) = 1 - P (X ≤ 84)

$=1-\sum _{x=0}^{x=84}\frac{e^{-64}(64)^{x}}{x!}\\=1-[e^{-64}\sum _{x=0}^{x=84}\frac{(64)^{x}}{x!}]\\=1-[e^{-64}[\frac{(64)^{0}}{0!}+\frac{(64)^{1}}{1!}+\frac{(64)^{2}}{2!}+...+\frac{(64)^{84}}{84!}]]\\=1-0.99308\\=0.00692\\\approx0.007$

Thus, the probability of the event (X > 84) is 0.007.

(b)

Compute the probability of the event (X < 64) as follows:

P (X < 64) = P (X = 0) + P (X = 1) + P (X = 2) + ... + P (X = 63)

$=\sum _{x=0}^{x=63}\frac{e^{-64}(64)^{x}}{x!}\\=e^{-64}\sum _{x=0}^{x=63}\frac{(64)^{x}}{x!}\\=e^{-64}[\frac{(64)^{0}}{0!}+\frac{(64)^{1}}{1!}+\frac{(64)^{2}}{2!}+...+\frac{(64)^{63}}{63!}]\\=0.48338\\\approx0.483$

Thus, the probability of the event (X < 64) is 0.483.

5 0

3 years ago