Answer:
6,true 7,false 8,false 9,true 10,true
Step-by-step explanation:
<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
The first three statements are correct while the last statement is incorrect.
Every point on the x-axis has y-coordinate 0.
Let y = 0, and solve for x.
y = -5x + 5
0 = -5x + 5
5x = 5
x = 1
The line crosses the x-axis at x = 1.
