All categories

2 years ago

As of 2009, the highest temperature ever recorded in Tennessee was 450 C . Find the corresponding Fahrenheit temperature.

Mathematics

1 answer:

nikitadnepr [17]2 years ago

8 0

The answer issssssas 842 F

You might be interested in

Which description does NOT guarantee that a quadrilateral is a square?

faltersainse [42]

A would be the correct answer

8 0

2 years ago

Robert is selling his bulldozer at a heavy equipment auction. The auction company receives a commission of 5% of the selling pri

kifflom [539]

Answer:

$131422

Step-by-step explanation:

Given :

Amount owed = $124,850

Commison on sale = 5%

Let :

Sale price of bulldozer = x

Sale price = amount owed + 5% of sale price

x = 124850 + 0.05*x

x = 124850 + 0.05x

x - 0.05x = 124850

0.95x = 124850

x = 124850 / 0.95

x = 131421.05263

To the nearest dollar = $131422

4 0

3 years ago

Help me I don’t understand

elena55 [62]

Answer:

It is B i think

6 0

2 years ago

Erin was able to map line segment \overline{AB}

horrorfan [7]

Answer:

There is no error

Step-by-step explanation:

6 0

2 years ago

Need help please!! Will give points

Nataly [62]

Answer:

1. $\bar X=5.10$

2. $\sigma=0.47$

3. $\sigma^2=0.22$

Step-by-step explanation:

QUESTION 1

The given data set for the expenditure is

$4.85,5.10,5.50,4.75,4.50,5.00,6.00$

The formula for calculating the mean is given by,

$\bar X=\frac{\sum x}{n}$

We need to add all the expenditure and divide by the total number of days.

$\bar X=\frac{4.85+5.10+5.50+4.75+4.50+5.00+6.00}{7}$

This gives us,

$\bar X=\frac{35.7}{7}$

$\Rightarrow \bar X=5.10$ to the nearest hundredth.

QUESTION 2

The standard deviation of the data set is given by the formula;

$\sigma =\sqrt{\frac{\sum(x-\bar X)^2}{n} }$

This implies that,

$\sigma =\sqrt{\frac{(4.85-5.10)^2+(5.10-5.10)^2+(5.50-5.10)^2+(4.75-5.10)^2+(4.50-5.10)^2+(5.00-5.10)^2+(6.00-5.10)^2}{7} }$

This will give us,

$\sigma =\sqrt{\frac{(-0.25)^2+(0.00)^2+(0.40)^2+(-0.35)^2+(-0.60)^2+(-0.10)^2+(0.90)^2}{7} }$

$\sigma =\sqrt{\frac{0.0625+0+0.16+0.1225+0.36+0.01+0.81}{7} }$

$\sigma =\sqrt{\frac{61}{280} }$

$\sigma =0.466775$

to the nearest hundredth,

$\sigma =0.47$ .

QUESTION 3

The variance is the square of the standard deviation.

$\sigma^2 =(0.46675)^2$

$\sigma^2 =0.217857$

To the nearest hundred gives,

$\sigma^2 =0.22$

3 0

3 years ago