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3 years ago

What is half of 750 i really need help

Mathematics

2 answers:

kondaur [170]3 years ago

8 0

$half =\frac{1}{2} \\\\ \frac{1}{2}*750= \boxed{375}$

Nady [450]3 years ago

4 0

I got 375 but someone else might have gotten something different have someone help you or use a calculator.

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3 years ago

he volume of a cone of radius r and height h is one-third the volume of a cylinder with the same radius and height. Does the su

antoniya [11.8K]

Answer:

The surface area of a cone of radius r and height h not equal to one-third the surface area of a cylinder with the same radius and height.

Relationship is $S_c=(\frac{\sqrt{(r+h)}}{2h})S_C$

Step-by-step explanation:

Given : The volume of a cone of radius r and height h is one-third the volume of a cylinder with the same radius and height.

To find : Does the surface area of a cone of radius r and height h equal one-third the surface area of a cylinder with the same radius and height?

If not, find the correct relationship. Exclude the bases of the cone and cylinder.

Solution :

Radius of cone and cylinder is 'r'.

Height of cone and cylinder is 'h'.

The volume of cone is $V_c=\frac{1}{3}\pi r^2 h$

The volume of cylinder is $V_C=\pi r^2 h$

$\frac{V_c}{V_C}=\frac{\frac{1}{3}\pi r^2 h}{\pi r^2 h}$

$V_c=\frac{1}{3}V_C$

i.e. volume of cone is one-third of the volume of cylinder.

Now,

Surface area of the cone is $S_c=\pi r\sqrt{(r+h)}$

Surface area of the cylinder is $S_C=2\pi rh$

Dividing both the equations,

$\frac{S_c}{S_C}=\frac{\pi r\sqrt{(r+h)}}{2\pi rh}$

$\frac{S_c}{S_C}=\frac{\sqrt{(r+h)}}{2h}$

$S_c=(\frac{\sqrt{(r+h)}}{2h})S_C$

Which clearly means $S_c\neq \frac{1}{3}S_C$

i.e. The surface area of a cone of radius r and height h not equal to one-third the surface area of a cylinder with the same radius and height.

The relationship between them is

$S_c=(\frac{\sqrt{(r+h)}}{2h})S_C$

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Neporo4naja [7]

We will prove first that PRQ≡PSQ
We need 3 attributes from the each triangle:
QS=QR
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We will prove that triangles RPO≡SPO
We need 3 attributes from the each triangle:
RP=PS
PO=PO
angles RPQ and SPQ are equal

results that angles RPO and SPO are equal(Let's note them with x)
We also know that (as angles) POS≡ROS and POR≡SOQ as opposite angles

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You just need to put this explanation into the table. (most if the 3 attributes for each triangle)

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