Question

Use the formula h=16t2, where t is time in seconds and h is the distance in feet traveled by a free-falling body or object to solve the following problem.A skywalk is 90 feet beyond the canyon's edge and is 4080 ft above the canyon floor.
Determine the time, to the nearest tenth of a second, it would take an object, dropped off the skywalk, to land at the bottom of the canyon.

Answer 1

Answer:

The time required is 15.97 second.

Step-by-step explanation:

Consider the provided information.

A skywalk is 90 feet beyond the canyon's edge and is 4080 ft above the canyon floor.

First find the distance between skywalk and canyon floor by using Pythagorean theorem.

Distance between skywalk and canyon's edge = $\sqrt{4080^2+90^2}$

Distance between skywalk and canyon's edge = $4080.99$

Substitute h = 4080.99 in the provided formula.

$4080.99=16t^2$

$t^2=255.062$

$t=15.97$

Hence, the time required is 15.97 second.