Answer:
Domain: 1 ≤ x ≤ 6, Range: 1 ≤ y ≤ 7
Answer:
19.
log9(5x^2 + 10) - log9(10) = 1
<=> log9((5x^2 + 10)/10) = log9(9)
<=> (5x^2 + 10)/10 = 9
<=> 5x^2 + 10 = 90
<=> 5x^2 = 80
<=> x^2 = 16
<=> x = +/- (4)
20.
log5(2x^2 + 4) + log5(3) = 2
<=> log5((2x^2 + 4) x 3) = log3(9)
<=> 6x^2 + 12 = 9
<=> 6x^2 = -3
=> No real x satisfies. ( x^2 always larger or equal to 0)
21.
log6(8) + log6(7 - 2x^2) = 2
<=> log6(8 x (7 - 2x^2)) = log6(36)
<=> 56 - 16x^2 = 36
<=> 16x^2 = 20
<=> x^2 = 5/4
<=> x = +/- sqrt(5/4)
Hope this helps!
:)
Answer:
d. x ≥ 2 or x ≤ -2
Step-by-step explanation:
The domain is the set of all possible x-values that will make the function work.
For the function to work, the radicand cannot be negative.
x² - 4 ≥ 0
x² ≥ 4
x ≥ 2 -x ≥ 2
x ≤ -2
The domain is x ≥ 2 and x ≤ -2.
The graph of your function shows that ƒ(x) does not exist when -2 < x < 2.