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irinina [24]
3 years ago
13

When a fish is selected at random from a tank, the probability that it has a green tail is 0.36, the probability that it has red

fins is 0.59, and the probability that it has both a green tail and red fins is 0.21. What is the probability that the selected fish will not have a red fin or a green tail?
Mathematics
1 answer:
Katarina [22]3 years ago
6 0

Answer: 0.26

Step-by-step explanation:

As per given , we have

P(green tail) = 0.36

P(red fins) = 0.59

P(both a green tail and red fins ) = 0.21

Now, P(Neither red fin nor green tail )= 1 - P(either red fin or green tail )

<em>[P(neither A nor B)= 1- P(either A or B)]</em>

= 1-(P(green tail) +P(red fins)+P(both a green tail and red fins ))

<em>[P(A or B)= P(A)+P(B)-P(A and B)]</em>

= 1- (0.36+0.59-0.21)

= 1-(0.74)

= 0.26

Hence, the probability that the selected fish will not have a red fin or a green tail = 0.26

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