Depending on what you need to round it to, it’s
1.9565
Or
1.957
Or
1.96

Density is mass/volume so it’s simply 4.8/2.3
Which equals
1.95652174

Hope this helped, good luck!

3 0

3 years ago

Read 2 more answers

The atomic number of nitrogen is 7. Nitrogen-15 has a greater mass number than nitrogen-14 because the atomic nucleus of nitroge

Varvara68 [4.7K]

The difference in the mass of the Nitrogen-14 and Nitrogen-15 atom is because nitrogen-15 has 8 neutrons while nitrogen-14 has 7 neutrons.

<h3>What is atomic mass of an element?</h3>

Atomic mass of an element is the sum of the masses of the protons and neutrons in the nucleus of an atom.

<h3>Why is the atomic mass of Nitrogen-14 and Nitrogen-15 different?</h3>

The difference in the mass of the Nitrogen-14 and Nitrogen-15 atom is due to the difference in the number of neutrons.

Nitogen-15 has 8 neutrons while nitrogen-14 has 7 neutrons.

Therefore, the difference in the mass of the Nitrogen-14 and Nitrogen-15 atom is because nitrogen-15 has 8 neutrons while nitrogen-14 has 7 neutrons.

Learn more about atomic mass at: brainly.com/question/8101390

5 0

3 years ago

Consider the hypothetical reaction A(g)←→2B(g). A flask is charged with 0.77 atm of pure A, after which it is allowed to reach e

ankoles [38]

<u>Answer:</u>

<u>For A:</u> The total pressure in the flask at equilibrium is 1.19 atm

<u>For B:</u> The value of $K_p$ for the given equation is 2.016

<u>Explanation:</u>

We are given:

Initial partial pressure of A = 0.77 atm

Equilibrium partial pressure of A = 0.35 atm

<u>For A:</u>

For the given chemical equation:

$A(g)\rightleftharpoons 2B(g)$

<u>Initial:</u> 0.77

<u>At eqllm:</u> 0.77-x 2x

Evaluating the value of 'x'

$\Rightarrow (0.77-x)=0.35\\\\x=0.42$

Equilibrium partial pressure of B = 2x = (2 × 0.42) = 0.84 atm

Total pressure in the flask at equilibrium = $p^A_{eq}+p^b_{eq}=[0.35+0.84]atm=1.19atm$

Hence, the total pressure in the flask at equilibrium is 1.19 atm

<u>For B:</u>

The expression of $K_p$ for given equation follows:

$K_p=\frac{(p_B)^2}{p_A}$

Putting values in above expression, we get:

$K_p=\frac{(0.84)^2}{0.35}\\\\K_p=2.016$

Hence, the value of $K_p$ for the given equation is 2.016

7 0

3 years ago

When water is ionized, it can act as either an acid or a base. <br> a. True <br> b. False?

kap26 [50]

True...
that's where brownsted- lowry theory comes into consideration ,where the idea of conjugate base and acid pair comes in..
eg when water dissociates it serves as both the acid and base
H20[acid] + H20[base] -> H30+ [base] + 0H- [acid]

5 0

3 years ago