Given that there is 48 liters of gasoline to be burned and that 45 kJ of energy is released per gram of gasoline burned, the amount of energy that the gasoline fuel produces can then be calculated, First, we convert 48 liters of gasoline to units of mass (grams) in order to use the given conversion of 45 kJ per gram of gasoline. To do this, we use the density of gasoline which is 0.77 g/mL. The following expression is then used:
48 L gasoline x 1000 mL/L x 0.77 g/mL x 45 kJ/g gasoline = 1663200 kJ
<span>The amount of energy produced by burning 48 L of gasoline was then determined to be 1663200 kJ. </span>
Answer:
The formula for the compound isB6Br7
Answer:
b. First determine the mass of the sample and then convert it to the number of atoms using Avogadro's number and the molar mass of the element.
Explanation:
a. First determine the mass of the sample and then convert it to the number of atoms using the molar mass of the element. <em>FALSE. </em>As the mass is in grams and molar mass is in g/mol. This result in the moles of each element, not its number of atoms.
b. First determine the mass of the sample and then convert it to the number of atoms using Avogadro's number and the molar mass of the element. <em>TRUE. </em>Mass and molar mass will result in moles of element. These moles could be converted in number of atoms using Avogadro's number that is in # atoms per mole.
c.Use atomic microscope to determine Avogadro's number, then determine the mass of the sample and convert it to the number of atoms. <em>FALSE. </em>An atomic microscope is not used to determine Avogadro's number.
d.Use atomic microscope to count each atom. <em>FALSE. </em>There is not possible to count every single atom in an element. There are more atoms in a drop of water than stars in the sky.
I hope it helps!
