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3 years ago

Bonding Story Mini Project

Chemistry

1 answer:

ioda3 years ago

4 0

There needs to be the story so that i can work with the 1st question

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Please help me for question 1 and 2

likoan [24]

Answer:-

1) 6 mol

2) Mo

Explanation: -

Mass of Ozone = 48 g

Chemical formula of ozone = O3

Molar mass of Ozone O 3 = 16 x 3 = 48 g mol-1

Number of moles of ozone = Mass / molar mass

= 48 g / 48 g mol-1

= 1 mol

According to Avogadro’s law, 1 mole of a substance has 6.02 x 10^ 22 molecules.

So 1 mol of O3 has 6.02 x 10^ 22 molecules of ozone.

Now each Ozone molecule has 3 atoms of oxygen.

So, 1 mol of ozone has 3 x 6.02 x 10^22 atoms of oxygen.

Sodium must have 2 x 3 x 6.02 x 10^22 atoms as per the question.

According to Avogadro’s law, 6.02 x 10^ 22 atoms are in 1 mol of sodium

So, for 2 x 3 x 6.02 x 10^22 atoms, there should be (1/ 6.02 x 10^ 22) x 2 x 3 x 6.02 x 10^22

= 6 mol of sodium.

Let the mass of M be m g

Formula of hexafluoride = MF6.

Mass of the hexafluoride = g + 6 x 19

= m + 114

Mass of M=0.250g

Moles of M = 0.250/m

Mass of MF6= 0.547g

Moles of MF6 = 0.547/ (m + 114)

We know 1 mole of M gives 1 mole of MF6.

0.250/m moles of M gives 0.250/m moles of MF6.

But number of moles of MF6 = 0.547/ (m + 114)

Thus

0.250/m = (0.547)/ (m +114))

0.250m + 0.250 x 114 = 0.547m

m = 0.250 x 114 / (0.547 -0.250)

= 96

We see from the given data that Mo is 96.

So M is Mo.

4 0

3 years ago

What happens to atomic radius as one looks from the top to the bottom of a group on the periodic table?

Elden [556K]

Atomic radius increases

5 0

3 years ago

Read 2 more answers

A county creates an park to protect a forest.

Hatshy [7]

Great for the ecosystem

3 0

4 years ago

Compared to H2S, the higher boiling point of H2O is due to the

KIM [24]

Answer:

2, stronger hydrogen bonding

Explanation:

3 0

3 years ago

Read 2 more answers

The plot shows the absorbance spectra for solutions of caffeine, benzoic acid, and Mountain Dew® soda, each in 0.010 M HCl . A p

Aliun [14]

Complete Question

The diagram of the complete question is shown on the first uploaded image.

Answer:

a) The approximate absorbance of benzoic acid at 228 nm? : A = 0.8

b) The molar absorptivity(∈)

of benzoic acid at 228 nm? : ∈ = $1.12 * 10^{4} M^{-1} cm^{-1}$

Explanation:

Looking at the absorbance spectra, we can see that the approximate absorbance of benzoic acid at 228 is 0.8.

mass concentration of benzoic acid = $8.74 \frac{mg}{L} =8.74 * 10^{-3} \frac{g}{L}$

the molar concentration of benzoic acid = (mass concentration of benzoic acid) / (molar mass of benzoic acid )

molar concentration of benzoic acid = $(8.74 *10^{-3} \frac{g}{L} ) /(122.12\frac{g}{mol} )$

molar concentration of benzoic acid = $7.157 * 10^{-5}M$

molar absorptivity (∈) of benzoic acid = (absorbance) /[ (molar concentration of benzoic acid ) × (path length) ]

∈ = (0.8) / [ ( $7.157 *10^{-5}M$ ) ×(1.00 cm)]

= $1.12 * 10^{4} M^{-1} cm^{-1}$

5 0

3 years ago