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jarptica [38.1K]
3 years ago
14

Bonding Story Mini Project

Chemistry
1 answer:
ioda3 years ago
4 0
There needs to be the story so that i can work with the 1st question
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What can you infer about copper and silver based on the position related to each other on the periodic table
velikii [3]
They're metals and they are in the same group/family
8 0
3 years ago
If you want to prepare 80.0 mL of 4.00M acid ,How many mL of 12.4 M HCl are required ?
Oksi-84 [34.3K]

M_{A}V_{A}=M_{B}V_{B}\\(80.0)(4.00)=V_{B}(12.4)\\V_{B}=\frac{(80.0)(4.00)}{12.4} \approx \boxed{25.8 \text{ mL}}

5 0
2 years ago
How many molecules are in 41.8 g of sulfuric acid
Anton [14]

Answer

× 10²³ molecules are in 41.8 g of sulfuric acid

Explanation

The first step is to convert 41.8 g of sulfuric acid to moles by dividing the mass of sulfuric acid by its molar mass.

Molar mass of sulfuric acid, H₂SO₄ = 98.079 g/mol

Mole=\frac{Mass}{Molar\text{ }mass}=\frac{41.8\text{ }g}{98.079\text{ }g\text{/}mol}=0.426187053\text{ }mol

Finally, convert the moles of sulfuric acid to molecules using Avogadro's number.

Conversion factor: 1 mole of any substance = 6.022 × 10²³ molecules.

Therefore, 0.426187053 moles of sulfuric acid is equal

\frac{0.426187053\text{ }mol}{1\text{ }mol}\times6.022×10²³\text{ }molecules=2.57\times10^{23}\text{ }molecules

Thus, 2.57 × 10²³ molecules are in 41.8 g of sulfuric acid.

3 0
1 year ago
Be sure to answer all parts. Show the overall reaction for formation of racemic 3−bromohexane from (E)−3−hexene by enterin
Viktor [21]

Answer:

See explanation

Explanation:

The mechanism for the formation of bromohexane from hexene has been clearly shown in the image attached to this answer.

Hexene is attacked by HBr and a carbocation is first formed as shown. The carbocation is flat and planar. it can be attacked on either face by the bromide ion.

Attack on either faces yields a racemic mixture of the R and S enantiomer as shown in the image.

You can use the mechanism shown to fill in the structures.

8 0
3 years ago
At 25 degrees, the rate constant for the first order decomposition of a pesticide solution is 6.40 x 10^-2 min^-2. If the starti
EastWind [94]
<span>If the initial amount is 1, the amount remaining at time t is exp(-rt), where r is the rate constant (.0064), and t is the time (62). The value of the exponential is 0.6725, and doing the obvious multiplication gives .0211 mole.

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
</span>
7 0
3 years ago
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