3 years ago

Need help with exponential functions quick 30 points

Mathematics

1 answer:

nexus9112 [7]3 years ago

4 0

Answer:

I believe the answer is C. I hope this helps.

Step-by-step explanation:

You might be interested in

..Urgent.. 600 students attend Ridgewood Junior High School. 10% of students bring their lunch to school everyday. How many stud

zysi [14]

Answer:

Number of student bring their lunch = 60

Step-by-step explanation:

Given:

Total number of student = 600

Student bring their lunch = 10%

Find:

Number of student bring their lunch

Computation:

Number of student bring their lunch = Total number of student x Student bring their lunch

Number of student bring their lunch = 600 x 10%

Number of student bring their lunch = 60

3 0

2 years ago

One number is five more than another number. If the square of the smaller number is 3 more than 3 times the larger number, what

11111nata11111 [884]

Answer:

6 and 11

Step-by-step explanation:

n1 = n + 5

ns^2 = 3 + 3nb

6^2 = 3 + 3(11)

36 = 3 + 33

11 = 6 + 5

3 0

1 year ago

Triangle ABC has vertices of A(-8,8),B(6,2),C(-2,1).Find the length of the median from C in triangle e abc

jekas [21]

First find midpoint of AB and lastly find the length of midpoint and C

8 0

2 years ago

Which word best describes the closing costs of a mortgage?

frozen [14]

I think the answer is C

5 0

3 years ago

For each of the -3.3 trials, and in the same sequence in which you entered the freezing points, enter your calculated values for

dedylja [7]

Answer:

The morality of the solution is calculated as 0.859 m. We are required to determine the freezing point depression constant of pure water. The freezing point depression of the solution is given as

$T_{f} = T_{p} -T_{s} = K_{f}$ * (morality of solution)

$T_{p}$ and $T_{s}$ are the freezing points of the pure solvent (water, 0°C) and $K_{f}$ = freezing point depression constant of water. Therefore,

$T_{f} = K_{f}$ *(0.859 m)

=====> (0°C) – (3.00°C) = $K_{f} *(0.859 m)$

=====> -3.00°C = $K_{f} *(0.859 m)$

Ignore the negative sign (since $K_{f}$ is positive) and get

$K_{f}$ = (3.00°C) / (0.859 m) = 3.492°C/m

The freezing point depression constant of the solvent is 3.5°C kg/mole

3.5 K.kg/mole (temperature differences are the same in Celsius and Kelvin scales).

3 0

2 years ago