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Annette [7]
3 years ago
8

Complete the factorization of 3x^2 – 10x + 8. 3x^2 – 10x + 8 = (x – ___ )( ___ x – 4)

Mathematics
2 answers:
Maslowich3 years ago
6 0

Answer:  The complete factorization of the given expression is (x-2)(3x-4).

Step-by-step explanation:  We are given to complete the factorization of the following quadratic expression :

E=3x^2-10x+8~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

To factorize the given expression, we need two integers with sum -10 and product 34. Those two integers are -6 and -4.

The factorization of expression (i) is as follows :

E\\\\=3x^2-10x+8\\\\=3x^2-6x-4x+8\\\\=3x(x-2)-4(x-2)\\\\=(x-2)(3x-4).

Thus, the complete factorization of the given expression is (x-2)(3x-4).

zlopas [31]3 years ago
4 0
You are looking for

x × ? = 3x^2

and

-4 × ? = 8

The first one is x × 3x = 3x^2

second one is -4 × -2 = 8

So your factored expression is

(x - 2)(3x - 4)
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Write the number 3.8 in the form a/b using integers
Juliette [100K]

Answer:

3.8 = 38/10

Step-by-step explanation:

The given number = 3.8

We have to write 3.8 in fraction form a/b

Here we have 1 digit after the decimal. To get rid off the decimal number, we need to multiply both the numerator and the denominator by 10 since we have to 1 digit after the decimal.

\frac{3.8 *10}{10}

= 38/10

Therefore, the answer is 3.8 = 38/10

Thank you.

6 0
3 years ago
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3 years ago
in this line of circles, the ratio of the red circles to blue circles is 1:3. how many more red circles would need to be added t
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3 years ago
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7 0
3 years ago
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

3 0
3 years ago
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