The expressions for each of the given statements are
a. 6 + z
b. 20 - x
c. x/6 - 8
d. x + 5/4
<h3>Writing an expression </h3>
From the question, we are to write an expression for each of the given statement
a. the sum of 6 and z
That is,
6 + z
b. the difference between 20 and x
That is,
20 - x
c. 8 less than the quotient of x divided by 6
That is,
x/6 - 8
d. x increased by 5 divided by 4
That is,
x + 5/4
Hence, the expressions for each of the given statements are
a. 6 + z
b. 20 - x
c. x/6 - 8
d. x + 5/4
Learn more on Writing an expression here: brainly.com/question/17651563
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Given,
The sum of three integers is 92
So,
Let,
The first integer be "x"
The second integer be "y"
The third integer be "z"
Now,
According to the question,
y = 3x ..............equation (1)
z = 2x - 10 .............. equation (2)
x + y + z = 92 ..............equation (3)
Now,
Substituting the value of "y" and "z" from equation (1) and (2), we get,
x + (3x) + (2x - 10) = 92
x + 3x + 2x - 10 = 92
6x - 10 = 92
6x = 92 + 10
x = 102 / 6
x = 17
Now,
substituting the value of "x" in equation (1)
y = 3 (17)
y = 51
Now,
Substituting the value of "x" in equation (2),
z = 2 (17 ) - 10
z = 34 - 10
z = 24
So, the numbers are 17, 51 and 24
NEVER HATE MATH!!!
Answer:
k=4
Step-by-step explanation:
An algebraic expression is, obviously, an expression with a variable.
"A number" would represent a variable, which, in this case, we'll use y.
So, 15 decreased by twice x.
15 - y x 2 =
I hope this helped :)
Standard form is
ax + by = c
Only choice A is in that form.
