All categories

3 years ago

What would my grade be if I have a 68 and I get a 95 on a test

Mathematics

1 answer:

Ganezh [65]3 years ago

4 0

Answer:

it depends if you've done alot of things in your grade if you havnt done much and that's one of your first grades then it with go up I'm just saying it will average around like 70-75 cause if you done a lot of things then it is all that averaged to 68 it won't go to 90 cause then an a- would be your average grades you've gotten

You might be interested in

Find −914+27. Write your answer as a fraction in simplest form.

vfiekz [6]

Answer:

- +=_

914-27=887

887 answer this fraction

5 0

3 years ago

The cosine law

romanna [79]

$\bf \textit{Law of sines}
\\ \quad \\
\cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c}\\\\
-------------------------------\\\\$

$\bf \cfrac{sin(88^o)}{39.9}=\cfrac{sin(A)}{31}\implies \cfrac{31\cdot sin(88^o)}{39.9}=sin(A)
\\\\\\
sin^{-1}\left[ \cfrac{31\cdot sin(88^o)}{39.9} \right]=sin^{-1}\left[ sin(A) \right]
\\\\\\
sin^{-1}\left[ \cfrac{31\cdot sin(88^o)}{39.9} \right]=\measuredangle A
\\\\\\
50.93841^o\approx \measuredangle A\qquad thus\qquad \measuredangle C\approx 41.0619^o$

3 0

4 years ago

Find (a) arc length and (b) Area of a sector.

barxatty [35]

Answer:

a) 29.45 cm (2 dp)

b) 220.89 cm² (2 dp)

Step-by-step explanation:

<u>Formula</u>

$\textsf{Arc length}=r \theta$

$\textsf{Area of a sector}=\dfrac{1}{2}r^2 \theta$

$\quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle in radians)}$

<u>Calculation</u>

Given:

$\theta=\dfrac{5 \pi}{8}$
r = 15 cm

$\begin{aligned}\implies \textsf{Arc length} & =r \theta\\& = 15\left(\dfrac{5 \pi}{8}\right)\\& = \dfrac{75}{8} \pi \\& = 29.45\: \sf cm\:(2\:dp)\end{aligned}$

$\begin{aligned} \implies \textsf{Area of a sector}& =\dfrac{1}{2}r^2 \theta\\\\ & = \dfrac{1}{2}(15^2) \left(\dfrac{5 \pi}{8}\right)\\\\& = \dfrac{225}{2}\left(\dfrac{5 \pi}{8}\right)\\\\ & = \dfrac{1125}{16} \pi \\\\& = 220.89 \: \sf cm^2\:(2\:dp)\end{aligned}$

5 0

2 years ago

#14

Oksanka [162]

Answer:

Because BC=AD=8, segment BC ≅ Segment AD. Because these are horizontal line segments, their slopes are 0 and they are parallel.

Segment BC and AD are opposite sides that are both congruent and parallel. So ABCD is a parallelogram by the opposite sides congruent theorem.

Step-by-step explanation:

So if you count the boxes of segment BC you will get 8, same for if you count the boxes that make up segment AD. If they are the same distance they are congruent. You can see how BC and AD are both horizontal lines. To find the slope you need to do the slope formula for BC and AD, which is y2-y1/x2-x1 in our case BC= 4-4/12-4 which equals 0/8. If you do the same formula for AD, you will get 0/8 making them congruent and the slope 0. If the opposite sides are congruent and parallel it has to be a parallelogram by the opposites and congruent theorem.

6 0

2 years ago

Please help brainliest for best

Jlenok [28]

Answer:

You can do something where someone locks one of your family members up and to find them they give you clues like the equation and once you get to them you have a lock combination

Step-by-step explanation:

Hope this helps!!

3 0

3 years ago

Read 2 more answers