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anyanavicka [17]
3 years ago
14

Let f(x)=-6x+3 and g(x)=5x+4. Find f•g and state its domain

Mathematics
2 answers:
ZanzabumX [31]3 years ago
7 0
F(x)=-6x+3
f(-6)=(-6*-6)+3
f=-13/2

g(x)=5x+4
g(5)=25+4
g(5)=29
g=29/5

Ima let u solve the rest :D
GuDViN [60]3 years ago
6 0

Answer:

f\cdot g=-30x^2-9x+12

Domain = All real numbers or (-∞,∞)

Step-by-step explanation:

The given functions are

f(x)=-6x+3

g(x)=5x+4

We need to find the function f•g and its domain.

f\cdot g=f(x)g(x)

f\cdot g=(-6x+3)(5x+4)

f\cdot g=-6x(5x+4)+3(5x+4)

f\cdot g=-6x(5x)-6x(4)+3(5x)+3(4)

f\cdot g=-30x^2-24x+15x+12

f\cdot g=-30x^2-9x+12

It is a polynomial of degree 2. Domain of a polynomial function is all real number.

Therefore, the domain of f•g is all real numbers.

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Answer:

<h2>d = 8</h2><h2>g = 2</h2>

Step-by-step explanation:

8d + 4 = 5d + 28

Group like terms

That's

8d - 5d = 28 - 4

3d = 24

Divide both sides by 3

d = 8

\frac{7(7g + 8)}{4}  = 38.5

Cross multiply

we have

7(7g + 8) = 38.5(4)

49g + 56 = 154

49g = 154 - 56

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Divide both sides by 49

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Hope this helps you

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3 years ago
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Step-by-step explanation:

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Very simple problem. Glad to help.

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In a state's Pick 3 lottery game, you pay $1.35 to select a sequence of three digits (from 0 to 9), such as 966. If you select t
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3 years ago
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Answer:

See explanations below

Step-by-step explanation:

The root of a quadratic equation is determined by its discriminant

D = b²-4ac

If D > 0, the roots are real and unique

If D < 0, the roots are complex

If D= 0, the roots are real and equal

a) For the quadratic equation

y=3x^2+7x+8

Since the highest degree of the equation is 2, hence the equation will have 2 roots

From the equation, a = 3,  b = 7 and c = 8

Get the discriminant

D = 7²-4(3)(8)

D = 49 - 96

D = -47

Since the discriminant value is less than 0, hence the roots are complex roots

b) For the quadratic equation

y=2x^2-7x-2

Since the highest degree of the equation is 2, hence the equation will have 2 roots

From the equation, a = 2,  b = -3 and c = -2

Get the discriminant

D = (-3)²-4(2)(-2)

D = 9 + 16

D = 25

Since the discriminant value is greater than 0, hence the roots are real and unique.

c) For the quadratic equation

y=9x^2+30x+25

Since the highest degree of the equation is 2, hence the equation will have 2 roots

From the equation, a = 9,  b = 30 and c = 25

Get the discriminant

D = 30²-4(9)(25)

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D = 0

Since the discriminant value is equal to 0, hence the roots are complex real and equal

7 0
3 years ago
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