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8090 [49]
3 years ago
12

I will mark you brainliest

Mathematics
1 answer:
mel-nik [20]3 years ago
5 0

Answer:

<h2><em>T O M E I T L O O K S A B O U T R I G H T.</em></h2>

Step-by-step explanation:

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Viktor [21]

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Step-by-step explanation:

0 \leq  x \leq  50

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Find the fifth term of an=3n-5
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4 0
3 years ago
Need help please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
lina2011 [118]

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8 0
3 years ago
For a function g(x), the difference quotient is StartFraction 6 Superscript x + h minus 3 Baseline minus 6 Superscript x + 3 Bas
kobusy [5.1K]

Answer:

The average rate of change in that interval is 1.99

Step-by-step explanation:

Here we have that the difference quotient for g(x) is:

\frac{6^{x + h} - 3 - 6^x + 3}{h}

Remember that for a general function f(x), the difference quotient is:

\frac{f(x + h) - f(x)}{h}

So if we look at the difference quotient for g(x), we can conclude that:

g(x) = 6^x - 3

Also remember that the average rate of change in an interval (a, b) is just:

\frac{g(b) - g(a)}{b - a}

So here we want the average rate of change of g(x) in the interval from x = -2 to x = 1, this is:

R = \frac{(6^1 - 3) - (6^{-2} - 3)}{1 - (-2)}  = \frac{6 - 6^{-2}}{3} = 1.99

The average rate of change in that interval is 1.99

8 0
3 years ago
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