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2 years ago

How I can apply the distribute property to this question?

Mathematics

1 answer:

igor_vitrenko [27]2 years ago

8 0

14 = 2•7 and 35 = 5•7, so the GCF of 14k and 35 is 7.

14k + 35 = 2•7k + 5•7 = 7 (2k + 5)

(Remember that the distributive property says a (b + c) = ab + ac.)

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3 years ago

AB lies on a number line. The coordinate of point A is -6. Given that AB=20, what are two possible coordinates for point B?

Dafna1 [17]

Answer:

Step-by-step explanation:

Given that

Coordinate of point A is -6.

Length of AB = 20

To find:

Coordinates for the point B = ?

Solution:

We are given that:

AB = 20

In other words, we can use modulus function to define the distance between A and B:

|Coordinates of B - Coordinates of A| = 20

Let the coordinates of B = $x$

Kindly refer to the attached image for the given situation.

Point B might be either on the left or on the right side of A.

That means:

$|x-(-6)| = 20\\\Rightarrow |x+6|=20$

Now, let us have a look at the modulus function:

$|y|=\left \{ {-{y}\ if\ y0} \right.$

So,

$|x+6|=\left \{ {-{(x+6)}\ if\ (x+6)0} \right.$

$(x+6 ) =20\\\Rightarrow x =14$

$-(x+6 ) =20\\\Rightarrow x =-26$

Therefore, the answer is:

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3 years ago

Triangle A″B″C″ is formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin. W

lesya692 [45]

Answer:

A)segment A"B"= AB / 2

Step-by-step explanation:

Triangle A″B″C″ is formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin. Which equation explains the relationship between segment AB and segment A"B"?

coordinate plane with triangle ABC at A(-3, 3), B(1, -3), and C(-3, -3)

A)segment A"B"= AB / 2

B)segment AB = segment A"B"/ 2

C)segment AB / segment A"B"= 1/2

D)segment A"B" / segment AB = 2

A"B" = AB / 2

Because

1. translations do not change the lengths of segments, so (x+2, y+0) preserves the length of AB, i.e. mA'B' = mAB

2. Dilation causes the new segment to be transformed to a new length according to the old length * the scale factor of (1/2).

Therefore A"B" = (1/2)AB, or AB/2.

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3 years ago