P(being delayed on M1) = 0.5 →P(NOT being delayed on M1) = 1-0.5 = 0.5
P(being delayed on M42)=0.75→P(NOT being delayed on M42) = 1-0.75= 0.25
P(NOT being delayed on M1) AND P(NOT being delayed on M42) = 0.5x0.25
→ 0.125 = 1/8
So, the chances he will not be delayed on his journey is 1/8
Beginning with the last deposit and working toward the present, the amount in the account is
3000 + 3000*1.06 + 3000*1.06^2 + 3000*1.06^3 + 3000*1.06^4
= 3000*(1.06^5 -1)/(1.06 -1)
= 16,911.28 . . . dollars
_____
The sum is found using the formula for the sum of a geometric series. For first term a1 and common ratio r, that sum is
Sn = a1*(r^n -1)/(r -1)
Your series has a1=3000 and r = 1.06. It has 5 terms (n=5).
<span>We can determine, a 30/25/15 series trade discount would be calculated as follows:
let X = retail price.
X - 0.30 </span>× X = Y ⇒ first discounted price.
<span>
Y - 0.25 </span>× Y = Z ⇒ second discounted price.
<span>
Z - 0.15*Z = T </span>⇒ total discounted price.
<span>
X - 0.30 </span>× X = (1 - 0.30) × X = 0.70 × X = Y
<span>
Y - 0.25 </span>× Y = (1 - 0.25) × Y = 0.75 × Y = Z
<span>
Z - 0.15 </span>× Z = (1 - 0.15) × Z = 0.85 × Z = T
<span>
since Z = 0.85 </span>× Y, then 0.85 × Z = 0.85 × 0.75 × Y
<span>
since Y = 0.70 </span>× X, then 0.85 × Z = 0.85 × 0.75 × 0.70 × X
<span>
based on the above, then T = total discount
= 0.85 </span>× 0.75 × 0.70 × X
= 0.44625X<span>
30/25/15 series discount is equivalent to a total discount of 44.625%
</span>
Answer:
I believe you solve the inequality so the answer is f < -3
if you click the image it will show you how to get the answer. I hope this helps you.
