Question

If a second resistor with R2 = 19.0 Ω is connected in series with R1, what is the total rate at which electrical energy is dissipated by the two resistors?

Answer 1

Total rate at which electrical energy is dissipated by the two resistors are V²/R  or I²R.

Explanation:

When the two resistors are combined in series then the total resistance gets added.

If $R_{1}$ and $R_{2}$ are in series then total resistance, R =

Total resistance becomes $R_{1}$ + 19 Ω

The total electrical power dissipated is equivalent to the power dissipated.

We know,

Power = V²/R  or

Power = I²R

where, V is the potential difference between the ends

            I is the current supplied.

Therefore, total speed at which electrical power is consumed by the two resistors are V²/R  or I²R.