Answer:
19600 N
Explanation:
weight = mass x gravity
We know that gravity = 9.8 m/s^2 and mass = 2000 kg.
w = m x g
w = 2000 kg x 9.8 m/s^2
w = 19600 N
The weight of the object is 19600 N (newtons).
Use the kinematics formula: y= yo+Vo-1/2at^2
Yo- initial position
Vo- initial velocity
Answer:
350 N
Explanation:
From the question given above, the following data were obtained:
Mass (m) of Go Kart = 35 kg
Initial velocity (u) = 12 m/s
Distance (s) = 7.2 m
Force (F) =?
Next, we shall determine the acceleration of the Go Kart. This can be obtained as follow:
Initial velocity (u) = 12 m/s
Distance (s) = 7.2 m
Final velocity (v) = 0 m/s
Acceleration (a) =.?
v² = u² + 2as
0² = 12² + (2 × a × 7.2)
0 = 144 + 14.4a
Collect like terms
0 – 144 = 14.4a
– 144 = 14.4a
Divide both side by 14.4
a = – 144 / 14.4
a = – 10 m/s²
The negative sign indicate that the Go Kart is decelerating when the brake was applied.
Finally, we shall determine the force the Go Kart have when the student locked the brake. This can be obtained as follow:
Mass (m) of Go Kart = 35 kg
Acceleration (a) = 10 m/s
Force (F) =?
F = ma
F = 35 × 10
F = 350 N
Thus, the Go Kart has a force of 350 N when the student locked the brake.
-- The overall <em>distance</em> he travels is (100m + 30m + 70m) = <em>200 meters</em>.
-- His <em>displacement </em>when he arrives at his front door is
D = (100m East) + (30m West) + (70m East)
D = (100m + 70m)East + (30m)West
D = (170m East) + (30m West)
<em>D = 140 meters East </em>
It's interesting to notice that his displacement is 60 meters shorter than the distance he walked.
That's because there's a stretch of 30 meters somewhere in the middle that he actually covered <em>three times</em>.
Two of those times added to the distance his shoes covered (2x30m=60m), but they cancelled out of the displacement.
His front door is 140 meters East of school. He walked 60m farther than that, going back and forth over the 30m piece.
