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ss7ja [257]
3 years ago
11

In a particular class of 28 students,8 students are men what fractions of the students is female in the class

Mathematics
2 answers:
WITCHER [35]3 years ago
8 0
20/28 are female. Since there are 8 male students you just have to subtract 28-8 and you'll get the female total.
nikdorinn [45]3 years ago
8 0
28 students.....8 are men...that means 20 are women

the fraction of the women in the class are : 20/28 which reduces to 5/7
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H/6 -1 = -3 Please help guys!
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Step-by-step explanation:

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4 0
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Solve the equation, and check the solutions (√x+3)+6=3.
larisa86 [58]

Answer:

The equation has no solution.

Step-by-step explanation:

Hi there!

First, let´s write the equation:

(√x + 3) + 6 = 3

To solve the equation, let´s subtract 6 to both sides of the equation:

√x + 3 = -3

subtract 3 to both sides of the equation:

√x = -6  (the square root of any number can´t be negative, but let´s solve it anyway and then check the solution).

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x = 36

(√36 + 3) + 6 = 3

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6 0
3 years ago
The equation of line AB is y 5x+ 1. Write an equation of a line paraliei to line AB in slope-intercept form that contains point
Alchen [17]

Answer:

The equation would be y = 5x - 15

Step-by-step explanation:

To find the equation to this line, we first have to note that parallel lines have the same slope. Since the original line has a slope of 5, we know that the new line will also have that slope. Then we can use the slope and the point in point-slope form and solve for y.

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7 0
3 years ago
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The Midpoint of AB dkdldl
Nutka1998 [239]
  • The Midpoint of AB is (1,0).

Given that:

  • In line AB, where the coordinates of A is (3,1) and coordinates of B is (-1,-1).

To find:

  • The Midpoint of line AB.

So, according the question

We know that,

The midpoint M of a line segment AB with endpoints A (x₁, y₁) and B (x₂, y₂) has the coordinates M ( \frac{x_1 + x_2}{2} , \frac{y_1 + y_2}{2} ).

Now from question,

We know that the the coordinates of A is (3,1) and coordinates of B is (-1,-1) of line AB.

So, we can say that

   A is (3,1) or x₁ = 3 and y₁ = 1.

   B (-1,-1) or x₂ = -1 and y₂ = -1.

∵ The coordinates of midpoint M (X,Y)

          X = \frac{x_1 + x_2}{2}

              = \frac{3-1}{2}

              = 2/2

          X = 1.

And

          Y = \frac{y_1 + y_2}{2}

              = \frac{1-1}{2}

              = 0/2

          Y = 0.

So, the midpoint of line AB is M (1,0)

To learn more about Midpoint of line, please click on the link;

brainly.com/question/14687140

#SPJ1

8 0
1 year ago
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