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Delicious77 [7]
3 years ago
5

When dividing with polynomials, the goal is to determine how many times the dividend divides evenly into the?

Mathematics
1 answer:
kkurt [141]3 years ago
5 0
Whether dividing constant terms or polynomials, we always have definitive terms when it comes to division. Suppose we say, 10x divided by 2. The dividend is the 10x and the divisor is the 2. In other words, the dividend is the number to be divided by the divisor, to obtain the answer called the quotient.

When dividing polynomials, your main goal is to be able to divide the dividend evenly into the <em>divisor</em>. For example, we divide x²+2x+1 by x+1. The first thing you're going to focus is, what term will completely divide the first term of the polynomial? That would be x. Why? Because when you multiply x with x+1, the product is x²+x. When you subtract this from the polynomial, the x² will cancel out. All you have to do is subtract x from 2x, yielding x. Then, you carry down the last term of the equation: +1. You do the steps again. The term that will completely divide x+1 by x+1 is 1. When you subtract the two, you will come up with zero. That means there is no remainder. The polynomial is divisible by the divisor. 
                          x + 1
                        ------------------------------------
                  x+1| x²+2x+1
                        - x²+x
                         ----------------------
                                 x +1
                               - x + 
                             ------------
                                    0
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Which of the following functions have a vertical asymptote for values of θ such that cos θ = 1? Select two answers.
valentina_108 [34]
Well costheta=1, at 0, 2pi,... 
knowing this we can exclude the first two as the are not undefined anywhere. 
tan is sin/cos, at 0 sin is also 0 so it becomes 0/1 which is 0, not undefined.
sec is1/cos, cos is 1, this is just 1
csc is 1/sin, sin is 0, 1/0 is undefined, meaning there will be an asymptote 
cot is cos/sin, this is again 1/0, so it is also an asymptote
The last two answers are the ones you want
3 0
3 years ago
A worker at a landscape design center uses a machine to fill bags with potting soil. Assume that the quantity put in each bag fo
defon

Answer:

a) The expected value is given by:

E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11

The variance is given by:

Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333

And the standard deviation is just the square root of the variance and we got:

Sd(x) = \sqrt{0.3333}= 0.5774

b) P(X

And we can use the cumulative distribution function given by:

F(x) = \frac{x-a}{b-a}, a \leq x \leq b

And using this function we got:

P(X

c) P(X>10.5)

And using the complement rule and the cumulative distribution function we got:

P(X>10.5)= 1-P(X

Step-by-step explanation:

For this case we define the random variable X=quantity put in each bag , and we know that the distribution for X is given by:

X \sim Unif (a= 10, b =12)

Part a

The expected value is given by:

E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11

The variance is given by:

Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333

And the standard deviation is just the square root of the variance and we got:

Sd(x) = \sqrt{0.3333}= 0.5774

Part b

For this case we want this probability:

P(X

And we can use the cumulative distribution function given by:

F(x) = \frac{x-a}{b-a}, a \leq x \leq b

And using this function we got:

P(X

Part c

For this case we want this probability:

P(X>10.5)

And using the complement rule and the cumulative distribution function we got:

P(X>10.5)= 1-P(X

3 0
3 years ago
Find the perimeter of A(-3,2), B(6,6), and C(7,-1).<br><br>Please show work.
Furkat [3]

AB=√{(6+3)²+(6-2)^2}=√(81+16)=√(97)

BC=√((7-6)²+(-1-6)²)=√(50)=5√2

AC=√((7+3)²+(-1-1)²)=2√(26)

Perimeter=AB+BC+AC=√97+5√2+2√(26)

3 0
3 years ago
What is the answer to (6x1^-5)(8x10^-9)
baherus [9]
That is kinda confusing

6 0
3 years ago
Of 300 children in a school 43% were boy. What percentage were girls &amp; how boys were there in the school
tia_tia [17]
57% is the answer to this question
8 0
3 years ago
Read 2 more answers
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