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MrRa [10]
3 years ago
7

PLEASE HELP !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Bond [772]3 years ago
8 0

Answer:

R = \frac {3ST}{2S + T}

Step-by-step explanation:

Given the equation;

\frac {3}{R} - \frac {1}{S} = \frac {2}{T}

Rearranging the equation, we have;

\frac {3}{R} = \frac {2}{T} + \frac {1}{S}

Lowest common multiple (LCM) of S and T is ST.

\frac {3}{R} = \frac {2S + T}{ST}

Cross-multiplying, we have;

3ST = R(2S + T)

Making R, the subject of formula;

R = \frac {3ST}{2S + T}

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Solve the solution using the substitution method <br><br>3x +5y = 29<br>y= -4x -1
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3x + 5y = 29         first equation
y = -4x - 1             second equation

substitute the second equation to the first equation;
3x + 5(-4x - 1) = 29
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solve for x;
-17x - 5 = 29
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x = -2

substitute x = -2 into the second equation to find y;
y = -4x - 1
y = -4(-2) - 1
y = 8 - 1
y = 7

so;
x = -2,  y = 7

hope this helps, God bless!
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