Hello from MrBillDoesMath!
Answer:
(3 /2)* ( x^(1/2) )
Discussion:
I think you are asking for the derivative of (3x) ^ (1/2) -- the square root of both 3 and x.
The derivative of (3x) ^ (1/2) is
(1/2) (3x) ^ (1/2 -1) (d(3x)/dx) =
(1/2) (3x)^(-1/2) 3 =
3/2 (1/ (3x)^ (1/2) ) =
3/2 ( 1/ 3^(1/2)) ( 1 / x^(1/2) ) =
(3/3^(1/2)) * (1/2) ( 1/ x^(1/2) ) =
( 3^(1/2) / 2 ) * (1/ x^(1/2) ) =
( 3^(1/2) ) * (1 / 2) * (1/ x^(1/2) ) =
It's straightforward but using a keyboard over complicates its appearance
Thank you,
MrB
The answer would be H, Because it is in the very center of both shapes which creates a line of symmetry which is used for the line of reflection
Hope this helped...
Answer:
answer is A. cosine
Step-by-step explanation:
Answer:
The equation of the line would be y = -1/3x - 4
Step-by-step explanation:
In order to find this, we first need to find the slope of the original line. We do this by solving for y.
2x + 6y = 10
6y = -2x + 10
y = -1/3x + 5/3
Now that we see the slope as -1/3, we know the new line will have the same slope thanks to the definition of parallel lines. So, we can use this slope and the point in point-slope form to find the equation.
y - y1 = m(x - x1)
y - -5 = -1/3(x - 3)
y + 5 = -1/3x + 1
y = -1/3x - 4
