Complete question:
The growth of a city is described by the population function p(t) = P0e^kt where P0 is the initial population of the city, t is the time in years, and k is a constant. If the population of the city atis 19,000 and the population of the city atis 23,000, which is the nearest approximation to the population of the city at
Answer:
27,800
Step-by-step explanation:
We need to obtain the initial population(P0) and constant value (k)
Population function : p(t) = P0e^kt
At t = 0, population = 19,000
19,000 = P0e^(k*0)
19,000 = P0 * e^0
19000 = P0 * 1
19000 = P0
Hence, initial population = 19,000
At t = 3; population = 23,000
23,000 = 19000e^(k*3)
23000 = 19000 * e^3k
e^3k = 23000/ 19000
e^3k = 1.2105263
Take the ln
3k = ln(1.2105263)
k = 0.1910552 / 3
k = 0.0636850
At t = 6
p(t) = P0e^kt
p(6) = 19000 * e^(0.0636850 * 6)
P(6) = 19000 * e^0.3821104
P(6) = 19000 * 1.4653739
P(6) = 27842.104
27,800 ( nearest whole number)
2 it’s literally just where the line crosses on the y axis
What you have to do is look at all the measurements (ft) and they are labeled. And some of the sides that aren't labeled have clues of what they could be. So when I added, I got 78 ft for my answer.
1)
C ≈ 3.14 • 9
C ≈ 28.26
The circumference is 28.3 cm to the nearest tenth of a centimeter
2)
C ≈ 3.14 (2 • 13)
C ≈ 3.14 • 26
C ≈ 81.64
The circumference is 81.6 in to the nearest tenth of a inch
3)
C = 3.14 (13)
C = 40.82
C = 40.8
4)
C = 3.14 (2 • 5)
C = 3.14 (10)
C = 31.4
5)
C = 3.14 (2 • 1.5)
C = 3.14(3)
C = 9.42
C = 9.4
