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3 years ago

Does Anyone Know How To Do This? Please help me

Mathematics

1 answer:

ad-work [718]3 years ago

7 0

Answer:(0,4,3i,-3i)

Step-by-step explanation:

x²(x²+9)-4x(x²+9)=0

(x²-4x)(x²+9)=0

x(x-4)=0

x₁=0

x₂=0+4=4

x₃=√-9=3i

x₄=√-9=-3i

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Answer These Questions and show your work to be brainliest

Andre45 [30]

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3 years ago

6m-4+3m+7 simplify term

Nady [450]

Answer:

9m +3

Step-by-step explanation:

6m-4+3m+7

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2 years ago

Read 2 more answers

In the figure below, Z is the center of the circle. Suppose that OR=4, ST= 4, UZ= 6, and VZ=4x-6. Find the following.

Ann [662]

Answer:

x = 3 units

SV = 2 units

Step-by-step explanation:

In $\odot Z$ QR and ST are chords such that:

QR = ST = 4

That is both the chords are equal in measure.

Equal chords are at equal distance from the center of the circle. Therefore,

VZ = UZ

4x - 6 = 6

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4x = 12

x = 12/4

x = 3 units

Since, perpendicular dropped from the center of the circle bisects the chord.

$\therefore SV = \frac{1}{2} ST$

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2 years ago

Solve ? <br><br>-4-4(-x-1)=-4(6+2x)

soldier1979 [14.2K]

$-4-4(-x-1)=-4(6+2x)\\\\-4+4x+4=-24-8x\\\\4x=-24-8x \ \ /+8x\\\\12x=-24 \ \ /:12\\\\\huge\boxed{x=-2}$

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3 years ago

What is the value of 4³÷ 2³ ?

Sunny_sXe [5.5K]

Answer:

2^3 or 8

Step-by-step explanation:

$4^3\div 2^3= \\\\(2^2)^3\div 2^3= \\\\2^{2\cdot 3}\div 2^3= \\\\2^6\div 2^3=\\\\2^{6-3}=\\\\2^3=\\\\8$

Hope this helps!

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3 years ago

Read 2 more answers