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DochEvi [55]
3 years ago
14

Emanuel surveyed a random sample of 50 subscribers to Auto Wheel magazine about the number of cars that they own. Of the subscri

bers surveyed, 15 own fewer than 2 vehicles. There are 340 subscribers to Auto Wheel magazine. Based on the data, what is the most reasonable estimate for the number of Auto Wheel magazine subscribers who own fewer than 2 vehicles? what would the awser be i dont get it
Mathematics
2 answers:
blondinia [14]3 years ago
8 0
102 would be the most reasonable estimate.

The experimental probability of owning fewer than 2 vehicles, based on the survey, is 15/50.  We multiply this probability by the number of subscribers to the magazine:

15/50(340) = 102
galben [10]3 years ago
6 0

Answer:

102

Step-by-step explanation:

It was correct on Khan Academy

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The University of Washington claims that it graduates 85% of its basketball players. An NCAA investigation about the graduation
Nonamiya [84]

Probabilities are used to determine the chances of events

The given parameters are:

  • Sample size: n = 20
  • Proportion: p = 85%

<h3>(a) What is the probability that 11 out of the 20 would graduate? </h3>

Using the binomial probability formula, we have:

P(X = x) = ^nC_x p^x(1 - p)^{n -x}

So, the equation becomes

P(x = 11) = ^{20}C_{11} \times (85\%)^{11} \times (1 - 85\%)^{20 -11}    

This gives

P(x = 11) = 167960 \times (0.85)^{11} \times 0.15^{9}

P(x = 11) = 0.0011

Express as percentage

P(x = 11) = 0.11\%

Hence, the probability that 11 out of the 20 would graduate is 0.11%

<h3>(b) To what extent do you think the university’s claim is true?</h3>

The probability 0.11% is less than 50%.

Hence, the extent that the university’s claim is true is very low

<h3>(c) What is the probability that all  20 would graduate? </h3>

Using the binomial probability formula, we have:

P(X = x) = ^nC_x p^x(1 - p)^{n -x}

So, the equation becomes

P(x = 20) = ^{20}C_{20} \times (85\%)^{20} \times (1 - 85\%)^{20 -20}    

This gives

P(x = 20) = 1 \times (0.85)^{20} \times (0.15\%)^0

P(x = 20) = 0.0388

Express as percentage

P(x = 20) = 3.88\%

Hence, the probability that all 20 would graduate is 3.88%

<h3>(d) The mean and the standard deviation</h3>

The mean is calculated as:

\mu = np

So, we have:

\mu = 20 \times 85\%

\mu = 17

The standard deviation is calculated as:

\sigma = np(1 - p)

So, we have:

\sigma = 20 \times 85\% \times (1 - 85\%)

\sigma = 20 \times 0.85 \times 0.15

\sigma = 2.55

Hence, the mean and the standard deviation are 17 and 2.55, respectively.

Read more about probabilities at:

brainly.com/question/15246027

8 0
3 years ago
If x metres of string are cut from a piece y metres long how much is left?
Karolina [17]

Answer: The new length is: (y - x) metres.

Step-by-step explanation:

If we have a piece of string that is y metres long, and we cut x metres of strings from it, then the new length of the string will be equal to the difference between the initial length and the amount that we cut off.

So the initial length is y metres.

We cut x metres.

The new length is: (y - x) metres.

6 0
3 years ago
Two-fifths of the senior class earned a grade of B+ or higher on an advanced mathematics exam.
matrenka [14]
2/5 = 42
1/5 = 21
5/5 = 105

105 students in the class
5 0
3 years ago
Read 2 more answers
PLS HELP ASAP
Mrrafil [7]
The answer is 2, yous add all of them up and divide by how many there are.
3 0
3 years ago
Given independent events A and B such that P(A) = 0.3 and P (B) = 0.5, which of the following is a correct statement?
aev [14]

Answer:

(D) P(AUB) = 0.65

Step-by-step explanation:

Since A and B are independent:

P(A ^ B)

= P(A) × P(B)

= 0.3 × 0.5 = 0.15

P(AUB) = P(A) + P(B) - P(A^B)

= 0.3 + 0.5 - 0.15

= 0.65

7 0
3 years ago
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