Using the BOX and WHISKER above, what is the LOWER QUARTILE of the information?

Mathematics

1 answer:

kifflom [539]2 years ago

6 0

Answer:

Lower Quartile is 8 according to the diagram.

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What is the markdown from $90 to $75?

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Answer:

$15.

Step-by-step explanation:

90-75=15, which is the difference between the two. Hope this helps.

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3 years ago

A sports news station wanted to know whether people who live in the North or the South are bigger sports fans. For its study, 17

Free_Kalibri [48]

Using the z-distribution, it is found that the 95% confidence interval for the difference is (-1.3, -0.7).

<h3>What are the mean and the standard error for each sample?</h3>

Considering the data given:

$\mu_S = 3.8, n = 175, s_S = \frac{1.7}{\sqrt{175}} = 0.1285$

$\mu_N = 4.8, n = 152, s_N = \frac{1.2}{\sqrt{152}} = 0.0973$

<h3>What is the mean and the standard error for the distribution of differences?</h3>

The mean is the subtraction of the means, hence:

$\overline{x} = \mu_S - \mu_N = 3.8 - 4.8 = -1$

The standard error is the square root of the sum of the variances of each sample, hence:

$s = \sqrt{s_S^2 + s_N^2} = \sqrt{0.1285^2 + 0.0973^2} = 0.1612$

<h3>What is the confidence interval?</h3>

It is given by:

$\overline{x} \pm zs$

We have a 95% confidence interval, hence the critical value is of z = 1.96.

Then, the bounds of the interval are given as follows:

$\overline{x} - zs = -1 - 1.96(0.1612) = -1.3$

$\overline{x} + zs = -1 + 1.96(0.1612) = -0.7$

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

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1 year ago

When 300 college students were surveyed, 220 said they own their car. Find a point estimate for p, the population proportion of

Scilla [17]

$\text{Hello there!}\\\\\text{Point estimates would be represented as:}\,\,p=\frac{x}{t}\\\\\text{"x" would represent the value you know}\\\\\text{"t" would represent your total}\\\\\text{To find your point value, you would divide 220 by 300}\\\\220\div300=0.73333333\\\\\text{Round to the nearest thousandths place}\\\\\boxed{0.733}$