Answer:
Let the width of the Rectangle be x inches
Then, length is (3x-5) inches
Perimeter of the Rectangle= 46 inches (given)
According to the above problem,
Equation :---- Perimeter=2(length+breadth)
<u>2{(3x-5)+x}=46</u>
2(4x-5)=46
(4x-5)=46/2=23
4x=(23+5)=28
x=28/4
<u>x=7</u>
So, length of the Rectangle is {(3×7)-5}=16 inches
and width is= 7 inches
Since the triangle is an equilateral triangle we know all of it's sides must be the same length, with that in mind the angles that make up the triangle must be equal as well. Knowing that a triangle's three interior angles make up 180 degrees we know that the size of each angle must be one third of this (as each angle must be equal).
180/3 = 60
then we may split the triangle along it's altitude into two special right triangles
more specifically two 30-60-90 triangles.
this means that the side with 30 degrees will be some value "x" where the side for 60 degrees will be related as it is "x*sqrt(3)" and the hypotenuse (which would be the side of the triangle) would be proportionally "2x"
this would mean that the altitude is the side associated with the 60 degree angle as such we can solve for "x" using this.
12= x*sqrt(3)
12/sqrt(3)=x
4sqrt(3)=x (simplifying the radical we get "x" equals 4 square root 3)
now we may solve for the side length of the triangle which is "2x"
2*4sqrt(3) -> 8sqrt (3)
eight square root of three is the answer.
I believe that it’s the first one
The first one would be x^12
