6 tenths or 6/10
it doesn't matter how many zeros you have after the .6 it's still 6 tenths. It can have a hundred zeros it will still be just .6 = 6/10 = 6 tenths
Hope that helps you. :-)
If he ate 4 of them, but it means he ate 2/5 muffins,
4 muffins = 2/5 muffins
You substitute x muffins for how much muffins she baked in all -
2/5* x muffins = 4
2/5 multiply by 2/5 to cross it out. Do the same to the other side.
x= 4 *5/2
x = 10 muffins
So there were 10 muffins in all
Answer:
see explanation
Step-by-step explanation:
Given
f(x) = ax + b
x = 2 → f(x) = 1 and x = - 1 → f(x) = - 5 ( from the table )
Substitute these values into f(x) = ax + b, that is
2a + b = 1 → (1)
- a + b = - 5 → (2)
Subtract (2) from (1) term by term to eliminate b
3a = 6 ( divide both sides by 3 )
a = 2
Substitute a = 2 into (2) and evaluate for b
- 2 + b = - 5 ( add 2 to both sides )
b = - 3
(b)
When x maps onto itself then
ax + b = x, that is
2x - 3 = x ( subtract x from both sides )
x - 3 = 0 ( add 3 to both sides )
x = 3
Thus a = 2, b = - 3 and x = 3
Answer:
- table: 14, 16, 18
- equation: P = 2n +12
Step-by-step explanation:
Perimeter values will be ...
rectangles . . . perimeter
1 . . . 14
2 . . . 16
3 . . . 18
__
The perimeter of a figure is twice the sum of the length and width. Here, the length is a constant 6. The width is n, the number of rectangles. So, the perimeter is ...
P = 2(6 +n) = 12 +2n
Your equation is ...
P = 2n +12 . . . . . . . . perimeter P of figure with n rectangles.
_____
<em>Additional comment</em>
You may be expected to write the equation using y and x for the perimeter and the number of rectangles. That would be ...
y = 2x +12 . . . . . . . . . perimeter y of figure with x rectangles
