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ElenaW [278]
2 years ago
7

Find the solutions of the quadratic equation

7x-14=0" alt="-x^2+7x-14=0" align="absmiddle" class="latex-formula">.
Choose 1 answer:
a) -\frac{7}{2}∓\frac{\sqrt{7}}{2}i
b) -\frac{7}{2}∓\frac{\sqrt{7}}{2}
c) \frac{7}{2}∓\frac{\sqrt{7}}{2}i
d) \frac{7}{2}∓\frac{\sqrt{7}}{2}
Mathematics
1 answer:
Vinvika [58]2 years ago
3 0

Answer:

Step-by-step explanation:

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3 years ago
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Solve 2x2 + 20x = −38. (1 point)
RoseWind [281]

Answer:

The solutions are x=-5+\sqrt{6}  and x=-5-\sqrt{6}


Step-by-step explanation:

we have

2x^{2} +20x=-38

Divide by 2 both sides

x^{2} +10x=-19 ------> x^{2} +10x+19=0

we know that


The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to


x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}


in this problem we have


x^{2} +10x+19=0

so


a=1\\b=10\\c=19


substitute

x=\frac{-10(+/-)\sqrt{10^{2}-4(1)(19)}}{2(1)}


x=\frac{-10(+/-)\sqrt{100-76}}{2}


x=\frac{-10(+/-)\sqrt{24}}{2}


x=\frac{-10(+/-)2\sqrt{6}}{2}


x1=\frac{-10(+)2\sqrt{6}}{2}=-5+\sqrt{6}


x2=\frac{-10(-)2\sqrt{6}}{2}=-5-\sqrt{6}


8 0
3 years ago
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