To solve the problem you must find the area of every square. For F one of the squares has a side length of 3 and because this is a square the other sides are also 3. To find the area we multiply two of the sides so 3 times 3 is 9
You do this with both the other squares
3*3=9
4*4=16
The area of the large square is given as 25
So 9+16=25 which means this is not the correct answer
H.
9*9=81
Given as 144
The area of the large square is 21*21 which is 441
144+81= 225
So because the two small squares DO NOT equal the area of the large square this is the correct answer.
Step-by-step explanation:
this creates a right-angled triangle.
the right angle (90°) being the angle between flag pole and ground.
the angle ground-wire is 50°.
because we know that the sum of all angles in a triangle is always 180°, we know then that the angle flagpole-wire is
180 - 90 - 50 = 40°
so, we have the situation to know 1 side and all angles.
to get the other sides we use best the law of sine :
a/sin(A) = b/sin(B) = c/sin(C)
where the sides and related angles are always opposite of each other.
in our case now we have
24/sin(50) = wire/sin(90) = wire/1 = wire = 31.32977494... ft
so, the rounded answer is that the wire must be
31.3 ft long
It is A because you subsitute the x in the equation A) (2x-8)(7x+5)=0 x=4 x=5,7 (fraction)
subtitute the x now and you get
(2(4)-8)(7(-5,7)+5) = 0
Answer:
Dimensions of original room = 12 x 12 feet.
Explanation:
Let the size of old square room be a x a.
New dimension = ( a+4 ) x ( a + 6 )
We have area of the new room will be 144 square feet greater than the area of the original room.
So, ( a+4 ) x ( a + 6 ) = a x a + 144
a²+10a+24= a²+144
10a = 120
a = 12 feet.
Dimensions of original room = 12 x 12 feet.
