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Tresset [83]
2 years ago
14

Image attachment below, Algebra 1 stuff

Mathematics
2 answers:
Fudgin [204]2 years ago
6 0

1.  11/2   

2.   1

3.  27

4.  2

5.  37

6.  54

7.  24

8.  x² +4x+2

chubhunter [2.5K]2 years ago
4 0
I know you didn't want an explanation, but I'll give you one anyway.
So, for a function, when you have f(5) = , then you'll put that 5 in for all of the x's in the function. 

The first batch of problems gave you the equation f(x) = \frac{x}{2} + 3. Now, plug in the numbers given for s and solve.

1. f(5) = <span>\frac{x}{2} + 3   Plug in 5 for x
</span>         = \frac{5}{2} + 3   Make three into a fraction over 2
         = \frac{5}{2} + <span>\frac{6}{2}   Add
         = </span><span><span>\frac{11}{2}

</span>2. f(-4) = </span><span>\frac{x}{2} + 3   Plug in -4 for x
           = </span><span>\frac{-4}{2} + 3   Divide -4 by 2
           = -2 + 3   Add
           = 1

For the next set, you have g(x) = x</span>² + 1.

3. Let's split this up. Solve the first equation, then the second, and then put         the answers together to solve it.

g(4) = x² + 1   Plug in 4 for x
       = 4² + 1   Square
       = 16 + 1   Add
       = 17

g(3) = x² + 1   Plug in 3 for x
       = 3² + 1   Square
       = 9 + 1   Add
       = 10

Now, put the two together.

g(4) + g(3) =    Substitute in the answers you just got.
      17 + 10 =    Add
                  = 27         

4. g(-1) = x² + 1      Substitute in -1 for x
            = (-1)² + 1   Square
            = 1 + 1        Add
            = 2

5. g(-6) = x² + 1       Plug in -6 for x
             = (-6)² + 1   Square
             = 36 + 1      Add
             = 37

For the last set, we have h(x) = x² + 7 and k(x) = 4x - 5. We'll have to pay close attention to the starting variables here.

6. h(-6) = x² + 7       Plug in -6 for x
             = (-6)² + 7   Square
             = 36 + 7      Add
             = 43

k(4) = 4x - 5     Plug in 4 for x
       = 4(4) - 5   Multiply
       = 16 - 5      Subtract
       = 11

Put the two answers into the final equation.

h(-6) + k(4) =    Substitute in the answers you got
       43 + 11 =    Add
                   = 54

7. k(10) = 4x - 5       Plug in 10 for x
            = 4(10) - 5   Multiply
            = 40 - 5      Subtract
            = 35

h(2) = x² + 7   Plug in 2 for x
       = 2² + 7   Square
       = 4 + 7     Add
       = 11

Now, put those into the equation.

k(10) - h(2) =    Plug in the answers you got
       35 - 11 =    Subtract
                  = 24

8. For this one, it wants you to add h(x) and k(x). We don't need to plug anything into the equations this time because they're both already solved for x! So, you can just set this up like a standard find-x equation.

(x² + 7) + (4x - 5) =
    x² + 7 + 4x - 5 =   Combine like terms (7 and -5)
         x² + 2 + 4x =    Reorder so the variables come first
                            = x² + 4x + 2

  
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Step-by-step explanation:

8) (5x + 23) + (17x - 41) = 180

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                                  x = 9

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6 0
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When Rafael emptied his pockets, e found he had a total of $3.50 in quarters and nickels. If he had 8 more quarters that nickels
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You can use systems of equations for this one.

We are going to use 'q' as the number of quarters Rafael had,
and 'n' as the number of nickels Rafael had.


You can write the first equation like this:
3.50=0.05n+0.25q
This says that however many 5 cent nickels he had, and however many
25 cent quarters he had, all added up to value $3.50.
Our second equation is this:
q=n+8
This says that Rafael had 8 more nickels that he had quarters.

We can now use substitution to solve our system.

We can rewrite our first equation from:
3.50=0.05n+0.25q
to:
3.50=0.05n+0.25(n+8)

From here, simply solve using PEMDAS.

3.50=0.05n+0.25(n+8)     --Distribute 0.25 to the n and the 8
3.50=0.05n+0.25n+2     --Subtract 2 from both sides
1.50=0.05n+0.25n     --Combine like terms
1.50=0.30n     --Divide both sides by 0.30
5=n     --This is how many NICKELS Rafael has.

We now know how many nickels he has, but the question is asking us
how many quarters he has.

Simply substitute our now-known value of n into either of our previous
equations (3.50=0.05n+0.25q or q=n+8) and solve.

We now know that Rafael had 13 quarters.

To check, just substitute our known values for our variables and solve.
If both sides of our equations are equal, then you know that you have
yourself a correct answer.

Happy math-ing :)
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Suppose the probability of success in a binomial event is 0.15. what is the probability of failure
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Answer:

Step-by-step explanation:

85

7 0
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