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nevsk [136]
3 years ago
8

How does a mirror affect the path of light?

Chemistry
2 answers:
Travka [436]3 years ago
7 0
C! I just took the test, Good luck!
Lilit [14]3 years ago
4 0

Answer:

c

Explanation:

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In one or two sentences, explain why the combined weight of several liquids mixed in an open flask can be less than but never mo
Rasek [7]

Answer:

Liquids in a form of mixture has less weight as compared to sum of all liquid's weight due to release of gases.

The combined weights of several liquids mixed in an open flask be less than the sum of all the weights of the liquids because when the reaction occurs new products are formed and also some gases which releases in the atmosphere.

These gases also contribute in the weight of the product so when it is released the weight of the mixture of liquids are less than the sum of the weights of all liquids so we can conclude that liquids in a form of mixture has less weight as compared to sum of all liquid's weight.

Explanation:

4 0
3 years ago
Read 2 more answers
Which of the following is the correct scientific notation for 0.000451 g?
german
4.5 x 10-4
An easy trick is to count the zeros.
6 0
3 years ago
Which of these is not a gas? hydrogen, oxygen, gravity, or helium
katrin2010 [14]

Answer:

I think that Gravity is not considered a gas but it can at the same time

Explanation:

Gasses are affected by gravity, as above video will prove. ... Yes, there is a attractive force between the gas molecules and gravity !

The rest are for sure gases

8 0
3 years ago
Read 2 more answers
Calculate ΔGrxn at 298 K under the conditions shown below for the following reaction.
algol13

Answer : The value of \Delta G_{rxn} is -24.9 kJ/mol

Explanation :

First we have to calculate the value of 'Q'.

The given balanced chemical reaction is,

Fe_2O_3(s)+3CO(g)\rightarrow 2Fe(s)+3CO_2(g)

The expression for reaction quotient will be :

Q=\frac{(p_{CO_2})^3}{(p_{CO})^3}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

Q=\frac{(2.1)^3}{(1.4)^2}

Q=3.375

Now we have to calculate the value of \Delta G_{rxn}.

The formula used for \Delta G_{rxn} is:

\Delta G_{rxn}=\Delta G^o+RT\ln Q    ............(1)

where,

\Delta G_{rxn} = Gibbs free energy for the reaction  = ?

\Delta G_^o =  standard Gibbs free energy  = -28.0 kJ/mol

R = gas constant = 8.314\times 10^{-3}kJ/mole.K

T = temperature = 298 K

Q = reaction quotient = 3.375

Now put all the given values in the above formula 1, we get:

\Delta G_{rxn}=(-28.0kJ/mol)+[(8.314\times 10^{-3}kJ/mole.K)\times (298K)\times \ln (3.375)

\Delta G_{rxn}=-24.9kJ/mol

Therefore, the value of \Delta G_{rxn} is -24.9 kJ/mol

5 0
3 years ago
What happens when a hydrocarbon combusts?
Anika [276]
I am pretty sure the answer is A
5 0
3 years ago
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