Ask question

Ask question

All categories

3 years ago

10

How many NADH are produced by glycolysis?

1 answer:

scZoUnD [109]3 years ago

6 0

There are 2 NADH produced by glycolysis.

You might be interested in

Select the formula for the following acid: Carbonic Acid

Nina [5.8K]

Answer: 106

Explanation:

Follow PEMDAS. 7x12 = 84

84 + 13 = 97

97 + 9 = 106

4 0

2 years ago

Classify the statements below as Weather or Climate. HELP ME WITH THIS The wind is blowing from the south. The average temperatu

ivanzaharov [21]

Answer:

Weather:

- The wind is blowing from the south.

- There is a thunderstorm warning.

- The average high temperatures for July in Yellowknife is 32.5 degrees Celcius.

- The wind is blowing at 56 km / hr.

Climate:

- The average temperature for February in Australia is 19 degrees Celsius.

- The average rainfall for June in Kenya is 3.3cm.

- 10mm of rain fell today.

- It is usually cold in Ottawa in January. -There was a cold weather advisory on Jan 21 2020.

-Hurricanes are most likely to hit the Gulf of Mexico and the Carribean.

Explanation:

Hope it helps.

6 0

3 years ago

the process of separating a liquid/solid mixture by slowly pouring the liquid component into a new vessel as the solid settles t

olga55 [171]

The process involving separation of liquid/solid mixture as regards this question is Decantation.

Decantation can be regarded as one of the process used in separation of liquid from solid as well as other immiscible (non-mixing) liquids through the removal of the liquid layer that is present at the top from the layer of solid/liquid which present at the below.

In the process, the liquid will be poured slowly into another vessel as the pouring continues, then the solid will settle in the original vessel.

This process can be done through tilting the mixture after the the top layer have been poured out.

<em>Therefore, decantation is one of the separation technique.</em>

Learn more at: brainly.com/question/16937734?referrer=searchResults

5 0

2 years ago

How can you tell if the content on a website is modified regularly?

Natalija [7]

A way you would be able to tell if a website is modified regularly is by looking for if the website is open to the public to write on.

4 0

3 years ago

Read 2 more answers

A 20.7167 g sample of impure magnesium carbonate was heated to complete decomposition according to the equation mgco3(s) → mgo(s

marishachu [46]

The mass of impure $MgCO_{3}$ is 20.7167 g. The decomposition reaction is as follows:

$MgCO_{3}(s)\rightarrow MgO(s)+CO_{2}(g)$

Here, 1 mole of $MgCO_{3}$ gives 1 mole of MgO.

Molar mass of $MgCO_{3}$ and MgO is 84.31 g/mol and 40.3044 g/mol respectively.

Converting number of moles in terms of mass,

$n=\frac{m}{M}$

Here, M is molar mass.

Since, $n_{MgCO_{3}}=n_{MgO}$

Thus, $\frac{m_{MgCO_{3}}}{M_{MgCO_{3}}}=\frac{m_{MgO}}{M_{MgO}}$

On putting the values,

$\frac{m_{MgCO_{3}}}{84.31}=\frac{m_{MgO}}{40.3044}$

Rearranging,

$m_{MgO}=\frac{m_{MgCO_{3}}}{84.31}\times 40.3044$

Or,

$m_{MgCO_{3}}=\frac{m_{MgO}}{0.4780}$ ...... (1)

Let the mass of impurity be $M_{I}$ and mass of impure $MgCO_{3}$ is 20.7167 g thus,

$M_{MgCO_{3}}=(20.7167-M_{I})g$ ...... (2)

Also, mass of impure MgO is 16.8817 g thus,

$M_{MgO}=(16.8817-M_{I})g$ ...... (3)

On comparing equations (2) and (3),

$M_{MgO}=M_{MgCO_{3}}-3.835$

Putting the value of $M_{MgO}$ in equation (1),

$m_{MgCO_{3}}=\frac{M_{MgCO_{3}}-3.835}{0.4780}$

Or,

$0.4780 M_{MgCO_{3}}=M_{MgCO_{3}}-3.835$

Or,

$M_{MgCO_{3}}-0.4780M_{MgCO_{3}}=3.835$

Or,

$0.522 M_{MgCO_{3}}=3.835$

Or,

$M_{MgCO_{3}}=\frac{3.835}{0.522}=7.35 g$

Thus, magnesium carbonate present in the original sample is 7.35 g.

5 0

3 years ago