Physical or mental traits change
The answer to that is mass and chemical
Calculando a massa molar (molar peso) Para Calcular a massa molar de hum Composto químico, ponha SUA fórmula E clique em 'Calcular'. Na Fórmula química that rápido Você PODE USAR: <span>QUALQUÉR elemento químico Grupos Funcionais: D, Ph, Me, Et, Bu, AcAc, Para, Ts, Tos, Bz, TMS, tBu, Bzl, Bn, Dmg PARENTESIS () UO colchetes [] . Nomes Comuns de Compostos. </span><span>Os Exemplos de Cálculos de Massa molar: </span> NaCl <span>, </span> o Ca (OH) 2 <span>, </span> K4 [Fe (CN) 6] <span>, </span> CuSO4 * 5H2O <span>, </span> água <span>, </span> ácido nítrico <span>, </span> permanganato de potássio <span>, </span> etanol <span>, </span> frutose . Peso Computação molecular (massa molecular) para calcular o peso molecular de um composto químico entrar em sua fórmula, especifique seu número de massa isotópica depois de cada elemento entre colchetes. <span>Os Exemplos de Cálculos de peso molecular:</span> C [14] o [16] 2 <span>,</span> S [34] O [16] 2 <span>.</span> Definição de massa molecular, o peso molecular, uma massa molar e do peso molar <span><span><span>Massa molecular</span></span></span><span><span> ( </span></span><span><span><span>peso molecular</span></span></span><span><span> ) e uma massa de uma molécula de uma substancia e e Expressa nsa unificadas unidades de massa atómica (u). </span></span><span><span>(1 u E igual a 1/12 da massa de hum átomo de carbono-12) </span></span><span><span><span>Massa Molar</span></span></span><span><span> ( </span></span><span><span><span>molar peso</span></span></span><span><span> ) E uma massa de Uma toupeira de Uma substancia ê ê expresso em g / mol.</span></span><span> Pesos dos Átomos e isótopos São de </span><span>NIST Artigo </span><span>.</span> DEIXE Seu comentário <span>Sobre a SUA Experiência com uma calculadora de Peso Molecular </span><span>Pesos </span><span>moleculares de Aminoacidos: Relacionados</span>
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Answer:
K₂CrO₅
Explanation:
The empirical formula is the simplest formula of a compound. To find the empirical formula, we follow the procedure below:
Elements Potassium Chromium Oxygen
Mass 6.52 4.34 5.34
Molar mass 39 60 16
Number of moles 6.52/39 4.34/60 5.34/16
0.167 0.072 0.333
Divide through by
the smallest 0.167/0.072 0.072/0.072 0.333/0.072
2.3 1 4.6
2 1 5
Empirical formula K₂CrO₅
Explanation:
a) The amount of heat released by coffee will be absorbed by aluminium spoon.
Thus, 
To calculate the amount of heat released or absorbed, we use the equation:
Also,
![m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_%7Bfinal%7D-T_1%29%3D-%5Bm_2%5Ctimes%20c_2%5Ctimes%20%28T_%7Bfinal%7D-T_2%29%5D)
..........(1)
where,
q = heat absorbed or released
= mass of aluminium = 45 g
= mass of coffee = 180 g
= final temperature = ?
= temperature of aluminium = 
= temperature of coffee = 
= specific heat of aluminium = 
= specific heat of coffee= 
Putting all the values in equation 1, we get:
![45 g\times 0.80J/g^oC\times (T_{final}-24^oC)=-[180 g\times 4.186J/g^oC\times (T_{final}-83^oC)]](https://tex.z-dn.net/?f=45%20g%5Ctimes%200.80J%2Fg%5EoC%5Ctimes%20%28T_%7Bfinal%7D-24%5EoC%29%3D-%5B180%20g%5Ctimes%204.186J%2Fg%5EoC%5Ctimes%20%28T_%7Bfinal%7D-83%5EoC%29%5D)
80.30 °C is the final temperature.
b) Energy flows from higher temperature to lower temperature.Whenever two bodies with different energies and temperature come in contact. And the resulting temperature of both bodies will less then the body with high temperature and will be more then the body with lower temperature.
So, is our final temperature of both aluminium and coffee that is 80°C less than initial temperature of coffee and more than the initial temperature of the aluminum.
