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3 years ago

6b < 24 or 4b + 12 > 4.

Mathematics

2 answers:

cestrela7 [59]3 years ago

4 0

The answer is -2<b<4 hoped I helped

castortr0y [4]3 years ago

3 0

The first one is b<4

The second one is b>-2

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Hi im maddie im only in 5th grade tgo but it says to express nine thousandsths as a decimal

monitta

Answer:

0.009

Step-by-step explanation:

Simply move the decimal point from nine- then move it to the right three times.

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From experience, it is known that on average 10% of welds performed by a particular welder are defective. if this welder is requ

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Binomial distribution can be used because the situation satisfies all the following conditions:1. Number of trials is known and remains constant (n)2. Each trial is Bernoulli (i.e. exactly two possible outcomes) (success/failure)3. Probability is known and remains constant throughout the trials (p)4. All trials are random and independent of the othersThe number of successes, x, is then given by $P(x)=C(n,x)p^x(1-p)^{n-x}$ where $C(n,x)=\frac{n!}{x!(n-x)!}$
Here we're given
p=0.10 [ success = defective ]
n=3

(a) x=0
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,0)0.1^0(1-0.1)^{3-0}$
$=1(1)(0.729)$
$=0.729$

(b) x=2
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,2)0.1^2(1-0.1)^{3-2}$
$=3(0.01)(0.9)$
$=0.027$

(c) x ≥ 2
$P(x)=\sum_{x=2}^3C(n,x)p^x(1-p)^{n-x}$
$=P(2)+P(3)$
$=C(n,2)p^2(1-p)^{n-2}+C(n,3)p^3(1-p)^{n-3}$
$=C(3,2)0.1^2(1-0.1)^{3-2}+C(3,3)0.1^3(1-0.1)^{3-3}$
$=3(0.01)(0.9)+1(0.001)1$
$=0.027+0.001$
$=0.028$

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3 years ago

Find the circumference of the circle. Use 3.14 for pi

IgorLugansk [536]

Answer:

The circumfrence is 14

Step-by-step explanation:

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50 is 40% of what number

Tpy6a [65]

125. To find the answer to these questions, divide the number (50) by the percent in decimal form (40% = 0.4) 50 / 0.4 = 125. To make sure, 125 x 0.4 = 50.

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3 years ago

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You're pretty sure that your candidate for class president has about 55% of the votes in the entire school. but you're worried t

Pavlova-9 [17]

Part A:

A component is one voter's vote. An outcome is a vote in favour of our candidate.
Since there are 100 voters, we can stimulate the component by using two randon digits from 00 - 99, where the digits 00 - 54 represents a vote for our candidate and the digits 55 - 99 represents a vote for the underdog.

Part B:

A trial is 100 votes. We can stimulate the trial by randomly picking 100 two-digits numbers from 00 - 99. Whoever gets the majority of the votes wins the trial.

Part C:

The response variable is whether the underdog wants to win or not. To calculate the experimental probability, divide the number of trials in which the simulated underdog wins by the total number of trials.

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