The area of this rectangle is x*y. But, this problem requires that you represent the variable "y" in terms of "x" only.
A hint here is that the variable "y" represent a point on the line that connects the end points (0,b) and (a,0).
The first step to solve this problem is to get the expression of this line.
The slope of this line is: m = (0 - b)/(a - 0) = -b/a
Because the point (x,y) is on this line we have: y - b = m(x - 0)
y = (-b/a)x + b
Solution: Area of the rectangle = x*y = x*((-b/a)x + b) = (-b/a)x2 +bx
Answer:
hypotenuse
Step-by-step explanation:
Remember that when using sin and cos functions, the hypotenuse is always included as the denominator of the equation EXCEPT when you're solving with tan, which is opposite/adjacent.
35+(18x)
35 is just advance while we have to pay 18 extra everyday
For this, we use simultaneous equations. Let George's page be g, Charlie's be c and Bill's page be b.
First, <span>George's page contains twice as many type words as Bill's.
Thus, g = 2b.
</span><span>Second, Bill's page contains 50 fewer words than Charlie's page.
Thus, b = c - 50.
</span>If each person can type 60 words per minute, after one minute (i.e. when 60 more words have been typed) <span>the difference between twice the number of words on bills page and the number of words on Charlie's page is 210.
We can express that as 2b - c = 210.
Now we need to find b, since it represents Bill's page.
We can substitute b for (c - 50) since b = c - 50, into the equation 2b - c = 210. This makes it 2(c - 50) - c = 210.
We can expand this to 2c - 100 - c = 210.
We can simplify this to c - 100 = 210.
Add 100 to both sides.
c - 100 + 100 = 210 + 100
Then simplify: c = 210 + 100 = 310.
Now that we know c, we can use the first equation to find b.
b = c - 50 = 310 - 50 = 260.
260 is your answer. I don't know where George comes into it. Maybe it's a red herring!</span>
Area of a circle=πr²
area of this cirlce=π*(12 ft)²=144π ft²≈452.39 ft².
answer 1= the area of this circle is 452.39 ft².
Perimeter of a circle=2πr.
Perimeter of this cirlce=2π(12 ft)=24π ft≈75.4 ft
<span>answer 2= the perimeter of this cirlce is 75.4 ft.</span>
