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Naddika [18.5K]
3 years ago
14

What is the initial temperature (°C) of a system that has the pressure decreased by 10 times while the volume increased by 5 tim

es with a final temperature of -123°C?
Chemistry
1 answer:
horrorfan [7]3 years ago
6 0

Answer:

27°C or 300K

Explanation

We were told that the pressureof the system decreased by 10 times implies that P2= P1/10

Where P2=final pressure

P1= initial pressure

Wew were also told that the volume of the system increased by 5 times this implies that V2= 5×V1

Where T2= final temperature =-123C= 273+(-123C)=150K

T1= initial temperature

But from gas law

PV=nRT

As n and R are constant

P1V1/T1 = P2V2/T2

T1= P1V1T2/P2V2

T1=2×T2

T1=2×150

T1=300K

=300-273

=27°C

the initial temperature (°C) of a system is 27°C

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What are the products of the chemical reaction between solutions of sodium bromide with a solution of silver nitrate?
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Answer : The products of the chemical reaction are, NaNO_3 and AgBr

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The balanced chemical reaction will be:

NaBr+AgNO_3\rightarrow NaNO_3+AgBr

The given reaction is a double-displacement reaction in which the cation of two reactants molecule exchange their places to give two different products.

The species present on the left side of the right arrow is the reactant and the species present on the right side of the right arrow is the product.

In the balanced chemical reaction,

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3 years ago
What happens if more product is added to a system at equalibrium
telo118 [61]

Answer:

When additional product is added, the equilibrium shifts to reactants to reduce the stress. If reactant or product is removed, the equilibrium shifts to make more reactant or product, respectively, to make up for the loss.

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emmasim [6.3K]

Answer:

\Delta _{fus}H=205J/g=13.03kJ/mol

Explanation:

Hello there!

In this case, since the heat of fusion is a property that allows us to calculate the heat involved during the change from solid to liquid (fusion) and is calculated as shown below:

Q=m*\Delta _{fus}H

In such a way, given the heat involved during this process and the mass of copper, we calculate the heat of fusion as shown below:

\Delta _{fus}H=\frac{Q}{m}=\frac{41000J}{200.g}\\\\\Delta _{fus}H=205J/g

Or in kJ/mol:

\Delta _{fus}H=205\frac{J}{gCu}*\frac{63.546 gCu}{1molCu}\\\\  \Delta _{fus}H=13026.93J/mol=13.03kJ/mol

Regards!

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