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Katen [24]
3 years ago
9

The empirical formula of a compound is determined to be CH2O, and its molecular mass is found to be 90.087 g/mol. Determine the

molecular formula of the compound, showing your work.
Chemistry
2 answers:
ElenaW [278]3 years ago
8 0

Answer:

molecular formula = C₃H₆O₃

Explanation:

The empirical formula is the simplest formula of a compound obtained by converting the moles of each atom to the simplest ratio.

In order to determine the molecular formula we will first calculate the empirical formula mass of compound.

Empirical formula mass = mass of C + 2 X mass of hydrogen + mass of O

Empirical formula mass = 12 + 2 +16 = 30

given molecular mass = 90.087

Let us divide the molecular mass by Empirical formula mass

ratio = 90.087 / 30 = 3 (approx)

Thus the molecular formula = 3 X empirical formula of compound

molecular formula = 3 (CH₂O)

molecular formula = C₃H₆O₃

IrinaVladis [17]3 years ago
6 0
To find the molecular formula of the compound, we get the molar mass of empirical formula CH2o which is 30 g/mol. We divided  the molecular mass of 90.087 g/mol by 30, we get 3. Hence, we multiply each element by 3, getting the molecular formula of C3H6O3.
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Ice Station Bravo near the North Pole launched a helium-filled balloon to check atmospheric conditions. At sea level (1.0 atm) w
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Answer:

12.9 m³ is the new volume

Explanation:

As the temperature keeps on constant, and the moles of the gas remains constant too, if we decrease the pressure, the volume will increase.  If the volume is decreased, pressure will be higher.

The relation is this: P₁ . V₁  = P₂  . V₂

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In conclusion and as we said, pressure has highly decreased so volume has highly increased.

8 0
3 years ago
A neutral atom of beryllium (Be) has an average mass of 9 amu and 4 electrons. How many neutrons does it have?
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8 0
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Identify the solute with the highest van't Hoff factor. And how do you determine which one is highest?
german

Answer : The correct option is, (A) AlCl_3

Explanation :

Van't Hoff factor : It is defined as the ratio of the experimental value of the colligative property to the calculated value of the colligative property.

We can determine the van't Hoff factor by the association and dissociation of the compound.

(A) AlCl_3

It is an electrolyte that dissociates to give aluminum ion and chloride ion.

The dissociation of AlCl_3 will be,

AlCl_3\rightarrow Al^{3+}+3Cl^{-}

So, Van't Hoff factor = Number of solute particles = Al^{3+}+3Cl^{-} = 1 + 3 = 4

(B) KI

It is an electrolyte that dissociates to give potassium ion and iodide ion.

The dissociation of KI will be,

KI\rightarrow K^{+}+I^{-}

So, Van't Hoff factor = Number of solute particles = K^{+}+I^{-} = 1 + 1 = 2

(C) CaCl_2

It is an electrolyte that dissociates to give calcium ion and chloride ion.

The dissociation of CaCl_2 will be,

CaCl_2\rightarrow Ca^{2+}+2Cl^{-}

So, Van't Hoff factor = Number of solute particles = Ca^{2+}+2Cl^{-} = 1 + 2 = 3

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It is an electrolyte that dissociates to give magnesium ion and sulfate ion.

The dissociation of MgSO_4 will be,

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So, Van't Hoff factor = Number of solute particles = Mg^{2+}+SO_4^{2-} = 1 + 1 = 2

(E) Non-electrolyte

The dissociation non-electrolyte is not possible. So, the Van't Hoff factor will always be, 1.

Hence, the highest van't Hoff factor of solute is, AlCl_3

7 0
3 years ago
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Answer:

You right!

Explanation:

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