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ikadub [295]
3 years ago
14

Rewrite the expression in the form... (PLZ HELP QUICK I'LL GIVE BRAINLIEST)

Mathematics
1 answer:
ivanzaharov [21]3 years ago
4 0

Answer: 3*z^\frac{2}{9}

Step-by-step explanation:

The exponent 1/3 is the same thing as cube rooting the expression.

\sqrt[3]{27\sqrt[3]{z^2} }

3*z^{2/9}

Hope it helps <3

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Someone plz help! Photo Above
TiliK225 [7]

Answer:

  • -704

Step-by-step explanation:

<u>Given the sequence</u>

  • A = -4 - 6i

<u>To find </u>

  • Sum of terms from i=5 to i=15
<h3>Solution</h3>

We see the sequence is AP

<u>The required sum is</u>

  • S₅₋₁₅ = S₁₅ - S₄

<u>Using sum of AP formula</u>

  • Sₙ = 1/2n(i₁ + iₙ)

<u>Finding the required terms</u>

  • i₁ = - 4- 6 = -10
  • i₄ = -4 -6*4 = - 28
  • i₁₅ = -4 -6*15 = -94

<u>Getting the sum</u>

  • S₄ = 1/2*4*(-10 - 28) = -76
  • S₁₅ = 1/2*15*(-10 - 94) = -780
  • S₅₋₁₅ = S₁₅ - S₄ = -780 - (-76) = - 704
4 0
3 years ago
What is the answer for this question 5 + (x^2 - xy) - 4
zzz [600]

Answer: x^2−xy+1

Step-by-step explanation:

simplify:

5+x^2−xy−4

5+x^2+−xy+−4

Combine Like Terms:

5+x^2+−xy+−4

(x^2)+(−xy)+(5+−4)

x^2+−xy+1

3 0
3 years ago
-X-5y + z = 17
grin007 [14]

Answer:

x = -1 , y = -4 , z = -4

Step-by-step explanation:

Solve the following system:

{-x - 5 y + z = 17 | (equation 1)

-5 x - 5 y + 5 z = 5 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Swap equation 1 with equation 2:

{-(5 x) - 5 y + 5 z = 5 | (equation 1)

-x - 5 y + z = 17 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Subtract 1/5 × (equation 1) from equation 2:

{-(5 x) - 5 y + 5 z = 5 | (equation 1)

0 x - 4 y+0 z = 16 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Divide equation 1 by 5:

{-x - y + z = 1 | (equation 1)

0 x - 4 y+0 z = 16 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Divide equation 2 by 4:

{-x - y + z = 1 | (equation 1)

0 x - y+0 z = 4 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Add 2 × (equation 1) to equation 3:

{-x - y + z = 1 | (equation 1)

0 x - y+0 z = 4 | (equation 2)

0 x+3 y - z = -8 | (equation 3)

Swap equation 2 with equation 3:

{-x - y + z = 1 | (equation 1)

0 x+3 y - z = -8 | (equation 2)

0 x - y+0 z = 4 | (equation 3)

Add 1/3 × (equation 2) to equation 3:

{-x - y + z = 1 | (equation 1)

0 x+3 y - z = -8 | (equation 2)

0 x+0 y - z/3 = 4/3 | (equation 3)

Multiply equation 3 by 3:

{-x - y + z = 1 | (equation 1)

0 x+3 y - z = -8 | (equation 2)

0 x+0 y - z = 4 | (equation 3)

Multiply equation 3 by -1:

{-x - y + z = 1 | (equation 1)

0 x+3 y - z = -8 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Add equation 3 to equation 2:

{-x - y + z = 1 | (equation 1)

0 x+3 y+0 z = -12 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Divide equation 2 by 3:

{-x - y + z = 1 | (equation 1)

0 x+y+0 z = -4 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Add equation 2 to equation 1:

{-x + 0 y+z = -3 | (equation 1)

0 x+y+0 z = -4 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Subtract equation 3 from equation 1:

{-x+0 y+0 z = 1 | (equation 1)

0 x+y+0 z = -4 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Multiply equation 1 by -1:

{x+0 y+0 z = -1 | (equation 1)

0 x+y+0 z = -4 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Collect results:

Answer: {x = -1 , y = -4 , z = -4

8 0
3 years ago
Can someone help me out
Rufina [12.5K]

Answer:

B

Step-by-step explanation:

6 0
3 years ago
Given: PS=RT, PQ=ST<br> Prove: QS=RS
ivanzaharov [21]

Answer:

I) Eq(1) reason: sum of segments of a straight line

II) Eq(2) reason: Given PQ = ST & PS = RT

III) Eq(3) reason: sum of segments of a straight line

IV) Eq(4) reason: Same value on right hand sides of eq(2) and eq(3) demands that we must equate their respective left hand sides

V) Eq(5) reason: Usage of collection of like terms and subtraction provided this equation.

Step-by-step explanation:

We are given that;

PS = RT and that PQ = ST

Now, we want to prove that QS = RS.

From the diagram, we can see that from concept of sum of segments of a straight line we can deduce that;

PQ + QS = PS - - - - (eq 1)

Now, from earlier we saw that PQ = ST & PS = RT

Thus putting ST for PQ & PS for RT in eq 1,we have;

ST + QS = RT - - - - (eq 2)

Again, from the line diagram, we can see that from concept of sum of segments of a straight line we can deduce that;

RS + ST = RT - - - - -(eq 3)

From eq(2) & eq(3) we can see that both left hand sides is equal to RT.

Thus, we can equate both left hand sides with each other to give;

ST + QS = RS + ST - - - (eq 4)

Subtracting ST from both sides gives;

ST - ST + QS = RS + ST - ST

This gives;

QS = RS - - - - (eq 5)

Thus;

QS = RS

Proved

5 0
3 years ago
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