All categories

3 years ago

Which numerical expression could represent this phrase?

Mathematics

1 answer:

Agata [3.3K]3 years ago

7 0

Answer:

Step-by-step explanation:

63 divided by 9 times 10 minus 2

You might be interested in

Suppose a scientist has 13 liters of acid and she needs 16 liters for an experiment.

vekshin1

B cause 13 plus x is equal to the 16 liters that u need and u already have 13 liters

3 0

2 years ago

Determine the quotient: 2 4/7 ÷ 1 3/6

Scilla [17]

First we must change these numbers to improper fractions:

$2\frac{4}{7}=\frac{18}{7}$

$1\frac{3}{6}=\frac{9}{6}$

So then we set it up:

$\frac{18}{7}$ ÷ $\frac{9}{6}$

When we divide fractions like this, we must flip the second fraction and change the sign from division to multiplication like so:

$\frac{18}{7}*\frac{6}{9}$

Then we solve:

$\frac{108}{63}$

Then if we divide the numerator and the denominator by 9, we get:

$\frac{12}{7}$ or, in mixed-number form, $1\frac{5}{7}$ .

4 0

3 years ago

Bert's bike shop has a $400 bicycle marked with a sign that says take a 35% discount what is the sale price

Inessa [10]

Answer:

$260

Step-by-step explanation:

Turn the percentage into a decimal.

35% -> 0.35

Multiply.

400 * 0.35 = 140

Subtract.

400 - 140 = $260

Best of Luck!

7 0

2 years ago

Read 2 more answers

Help me againnnnnnnnnnnnnnnnnnnnnnn

OLEGan [10]

Step-by-step explanation:

(2m + 4) / 8 = w

2m + 4 = 8w

2m = 8w - 4

m = 4w - 2

8 0

2 years ago

Read 2 more answers

Find the derivative of the function at P 0 in the direction of A. f(x,y,z) = 3 e^x cos(yz), P0 (0, 0, 0), A = - i + 2 j + 3k

Alik [6]

The derivative of $f(x,y,z)$ at a point $p_0=(x_0,y_0,z_0)$ in the direction of a vector $\vec a=a_x\,\vec\imath+a_y\,\vec\jmath+a_z\,\vec k$ is

$\nabla f(x_0,y_0,z_0)\cdot\dfrac{\vec a}{\|\vec a\|}$

We have

$f(x,y,z)=3e^x\cos(yz)\implies\nabla f(x,y,z)=3e^x\cos(yz)\,\vec\imath-3ze^x\sin(yz)\,\vec\jmath-3ye^x\sin(yz)\,\vec k$

and

$\vec a=-\vec\imath+2\,\vec\jmath+3\,\vec k\implies\|\vec a\|=\sqrt{(-1)^2+2^2+3^2}=\sqrt{14}$

Then the derivative at $p_0$ in the direction of $\vec a$ is

$3\,\vec\imath\cdot\dfrac{-\vec\imath+2\,\vec\jmath+3\,\vec k}{\sqrt{14}}=-\dfrac3{\sqrt{14}}$

3 0

3 years ago