Qx+12=13x+P with only one solution

Mathematics

2 answers:

ra1l [238]3 years ago

4 0

What are you solving for? if you are solving for x, then x=(P-12)/(Q-13)

AlexFokin [52]3 years ago

3 0

The answer to the question is: SimplifyingQx + 12 = 13x + P Reorder the terms: 12 + xQ = 13x + P Reorder the terms: 12 + xQ = P + 13x Solving 12 + xQ = P + 13x Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-13x' to each side of the equation. 12 + -13x + xQ = P + 13x + -13x Combine like terms: 13x + -13x = 0 12 + -13x + xQ = P + 0 12 + -13x + xQ = P Add '-12' to each side of the equation. 12 + -13x + -12 + xQ = -12 + P Reorder the terms: 12 + -12 + -13x + xQ = -12 + P Combine like terms: 12 + -12 = 0 0 + -13x + xQ = -12 + P -13x + xQ = -12 + P Reorder the terms: 12 + -1P + -13x + xQ = -12 + P + 12 + -1P Reorder the terms: 12 + -1P + -13x + xQ = -12 + 12 + P + -1P Combine like terms: -12 + 12 = 0 12 + -1P + -13x + xQ = 0 + P + -1P 12 + -1P + -13x + xQ = P + -1P Combine like terms: P + -1P = 0 12 + -1P + -13x + xQ = 0 The solution to this equation could not be determined. Hope this helps:)

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Given

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Required

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This means that at least one of the selected piece is defected.

So, we first calculate the probability that all the selected piece are accepted.

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