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katrin [286]
3 years ago
11

Qx+12=13x+P with only one solution

Mathematics
2 answers:
ra1l [238]3 years ago
4 0
What are you solving for? if you are solving for x, then x=(P-12)/(Q-13)
AlexFokin [52]3 years ago
3 0
The answer to the question is: Simplifying<span>Qx + 12 = 13x + P Reorder the terms: 12 + xQ = 13x + P Reorder the terms: 12 + xQ = P + 13x Solving 12 + xQ = P + 13x Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-13x' to each side of the equation. 12 + -13x + xQ = P + 13x + -13x Combine like terms: 13x + -13x = 0 12 + -13x + xQ = P + 0 12 + -13x + xQ = P Add '-12' to each side of the equation. 12 + -13x + -12 + xQ = -12 + P Reorder the terms: 12 + -12 + -13x + xQ = -12 + P Combine like terms: 12 + -12 = 0 0 + -13x + xQ = -12 + P -13x + xQ = -12 + P Reorder the terms: 12 + -1P + -13x + xQ = -12 + P + 12 + -1P Reorder the terms: 12 + -1P + -13x + xQ = -12 + 12 + P + -1P Combine like terms: -12 + 12 = 0 12 + -1P + -13x + xQ = 0 + P + -1P 12 + -1P + -13x + xQ = P + -1P Combine like terms: P + -1P = 0 12 + -1P + -13x + xQ = 0 The solution to this equation could not be determined. Hope this helps:)

</span>
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Step-by-step explanation:

Let the number is a <em>and</em><em> </em>b

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so,a+b=30 <em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>(</em><em>1</em><em>)</em>

The difference of two number =12

so,a-b=12<em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>(</em><em>2</em><em>)</em>

If we add two equation (1) and (2)

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\tt{ a=\dfrac{42}{2}  }

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\tt{ the~two~ number~ are~ 21 ~and~ 9  }

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