Answer:
A. y = 
x - 2
Step-by-step explanation:
The largest possible volume of the given box is; 96.28 ft³
<h3>How to maximize volume of a box?</h3>
Let b be the length and the width of the base (length and width are the same since the base is square).
Let h be the height of the box.
The surface area of the box is;
S = b² + 4bh
We are given S = 100 ft². Thus;
b² + 4bh = 100
h = (100 - b²)/4b
Volume of the box in terms of b will be;
V(b) = b²h = b² * (100 - b²)/4b
V(b) = 25b - b³/4
The volume is maximum when dV/db = 0. Thus;
dV/db = 25 - 3b²/4
25 - 3b²/4 = 0
√(100/3) = b
b = 5.77 ft
Thus;
h = (100 - (√(100/3)²)/4(5.77)
h = 2.8885 ft
Thus;
Largest volume = [√(100/3)]² * 2.8885
Largest Volume = 96.28 ft³
Read more about Maximizing Volume at; brainly.com/question/1869299
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The <em><u>correct answer</u></em> is:
$72.31 – $24.61 – $16.49; $31.21
Explanation:
We know we end the month with $72.31.
We made two deposits during the month and no other activity. This means if we take the amounts of the deposits away from the total at the end of the month, we can find how much we had at the beginning of the month:
72.31-24.61-16.49 = 31.21
Answer:
6 units
Step-by-step explanation:
(-4 , -10) ; (-4 , -4)
Distance = 
![= \sqrt{(-4-[-4])^{2}+(-4-[-10])^{2}}\\\\= \sqrt{(-4+4)^{2}+(-4+10)^{2}}\\\\=\sqrt{0+(6)^{2}}\\\\= \sqrt{36}\\\\= 6](https://tex.z-dn.net/?f=%3D%20%5Csqrt%7B%28-4-%5B-4%5D%29%5E%7B2%7D%2B%28-4-%5B-10%5D%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%20%5Csqrt%7B%28-4%2B4%29%5E%7B2%7D%2B%28-4%2B10%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B0%2B%286%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%20%5Csqrt%7B36%7D%5C%5C%5C%5C%3D%206)
Step-by-step explanation:
AB · BE = CB · BD Given
CB/BE = AB/BD Division Property of Equality
<ABC = <DBE Vertical angles are equal
ΔABC ≅ ΔDBE SAS Similarity Theorem
Hope it helps
