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3 years ago

In your own words, explain how decomposing a regular polygon into triangles can be used to determine the area of the figure.

Mathematics

1 answer:

AysviL [449]3 years ago

5 0

Answer:

It is very easy to find the area of triangles, and if we can turn a polygon into triangles, then we can find the area of the polygon easier.

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3 years ago

Three circular arcs of radius units bound the region shown. Arcs and are quarter-circles, and arc is a semicircle. What is the a

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Three circular arcs of radius $5$ units bound the region shown. Arcs $AB$ and $AD$ are quarter-circles, and arc $BCD$ is a semicircle.

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2 years ago

There are 35 female performers in a dance recital. The ratio of men to women in the recital is 2 : 7 How many men are in the rec

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3 years ago

if a single card is drawn from a standard 52- card deck in how many ways can a card other than a heart be obtained

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Step-by-step explanation:

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2 years ago

Read 2 more answers

Pleasee help ASAP!! No links pleaseee!!!

Ilya [14]

Given:

The vertices of the rectangle ABCD are A(0,1), B(2,4), C(6,0), D(4,-3).

To find:

The area of the rectangle.

Solution:

Distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using the distance formula, we get

$AB=\sqrt{(2-0)^2+(4-1)^2}$

$AB=\sqrt{(2)^2+(3)^2}$

$AB=\sqrt{4+9}$

$AB=\sqrt{13}$

Similarly,

$BC=\sqrt{(6-2)^2+(0-4)^2}$

$BC=\sqrt{(4)^2+(-4)^2}$

$BC=\sqrt{16+16}$

$BC=\sqrt{32}$

$BC=4\sqrt{2}$

Now, the length of the rectangle is $AB=\sqrt{13}$ and the width of the rectangle is $BC=4\sqrt{2}$ . So, the area of the rectangle is:

$A=length \times width$

$A=\sqrt{13}\times 4\sqrt{2}$

$A=4\sqrt{26}$

$A\approx 20$

Therefore, the area of the rectangle is 20 square units.

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3 years ago