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Anettt [7]
3 years ago
12

In your own words, explain how decomposing a regular polygon into triangles can be used to determine the area of the figure.

Mathematics
1 answer:
AysviL [449]3 years ago
5 0

Answer:

It is very easy to find the area of triangles, and if we can turn a polygon into triangles, then we can find the area of the polygon easier.

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salma has been given a list of 5 bands and asked to place a vote. her vote must have the names of her favorite and second favori
AysviL [449]

Answer:2 votes are possible

Step-by-step explanation:

7 0
3 years ago
The article "Students Increasingly Turn to Credit Cards" (San Luis Obispo Tribune, July 21, 2006) reported that 37% of college f
Sloan [31]

Answer:

Step-by-step explanation:

Hello!

There are two variables of interest:

X₁: number of college freshmen that carry a credit card balance.

n₁= 1000

p'₁= 0.37

X₂: number of college seniors that carry a credit card balance.

n₂= 1000

p'₂= 0.48

a. You need to construct a 90% CI for the proportion of freshmen  who carry a credit card balance.

The formula for the interval is:

p'₁±Z_{1-\alpha /2}*\sqrt{\frac{p'_1(1-p'_1)}{n_1} }

Z_{1-\alpha /2}= Z_{0.95}= 1.648

0.37±1.648*\sqrt{\frac{0.37*0.63}{1000} }

0.37±1.648*0.015

[0.35;0.39]

With a confidence level of 90%, you'd expect that the interval [0.35;0.39] contains the proportion of college freshmen students that carry a credit card balance.

b. In this item, you have to estimate the proportion of senior students that carry a credit card balance. Since we work with the standard normal approximation and the same confidence level, the Z value is the same: 1.648

The formula for this interval is

p'₂±Z_{1-\alpha /2}*\sqrt{\frac{p'_2(1-p'_2)}{n_2} }

0.48±1.648* \sqrt{\frac{0.48*0.52}{1000} }

0.48±1.648*0.016

[0.45;0.51]

With a confidence level of 90%, you'd expect that the interval [0.45;0.51] contains the proportion of college seniors that carry a credit card balance.

c. The difference between the width two 90% confidence intervals is given by the standard deviation of each sample.

Freshmen: \sqrt{\frac{p'_1(1-p'_1)}{n_1} } = \sqrt{\frac{0.37*0.63}{1000} } = 0.01527 = 0.015

Seniors: \sqrt{\frac{p'_2(1-p'_2)}{n_2} } = \sqrt{\frac{0.48*0.52}{1000} }= 0.01579 = 0.016

The interval corresponding to the senior students has a greater standard deviation than the interval corresponding to the freshmen students, that is why the amplitude of its interval is greater.

8 0
3 years ago
a triangle has a base that is 3 times longer than its height. it has a area of 486 sq cm. what is the base and height
saw5 [17]
B = 3h . . . . . . . .given by the problem statement
A = (1/2)bh . . . . formula for the area of a triangle

486 cm² = (1/2)*(3h)*h . . . substitute given information
(2/3)*486 cm² = h² . . . . . .multiply by 2/3
√324 cm = h . . . . . . . . . . . . . .take the square root

The height is 18 cm.
The base is 3*18 = 54 cm.
6 0
2 years ago
A 90 ° angle is divided into 2 angles. Find the size of the angles. 3x+15 and 2x+25
fenix001 [56]

The two angles are 45 degrees.

Step-by-step explanation:

You are just halfing the 90 degree angle, so all you have to do is divide 90 by two, and you have 45.

3 0
2 years ago
What is the least common denominator for 1/8, 1/9 and 1/12
Alona [7]
The least common denominator for 1/8, 1/9 and 1/12 is 24
5 0
2 years ago
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