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maxonik [38]
3 years ago
5

Learning Goal: How do 2 ordinary waves build up a "standing" wave? A very generic formula for a traveling wave is: y1(x,t)=Asin(

kx−ωt). This general mathematical form can represent the displacement of a string, or the strength of an electric field, or the height of the surface of water, or a large number of other physical waves!
Part C Find ye(x) and yt(t). Remember that yt(t) must be a trig function of unit amplitude. Express your answers in terms of A, k, x, ω, and t. Separate the two functions with a comma. Use parentheses around the argument of any trig functions.

Part E At the position x=0, what is the displacement of the string (assuming that the standing wave ys(x,t) is present)? Part G From

Part F we know that the string is perfectly straight at time t=π2ω. Which of the following statements does the string's being straight imply about the energy stored in the string?

a.There is no energy stored in the string: The string will remain straight for all subsequent times.

b.Energy will flow into the string, causing the standing wave to form at a later time.

c.Although the string is straight at time t=π2ω, parts of the string have nonzero velocity. Therefore, there is energy stored in the string.

d.The total mechanical energy in the string oscillates but is constant if averaged over a complete cycle.
Physics
1 answer:
zheka24 [161]3 years ago
3 0

Answer:

Explanation:

=Asin(kx−ωt). This general mathematical form can represent the displacement of a string, or the strength of an electric field, or the height of the surface of water, or a large number of other physical waves!

Part C Find ye(x) and yt(t). Remember that yt(t) must be a trig function of unit amplitude. Express your answers in terms of A, k, x, ω, and t. Separate the two functions with a comma. Use parentheses around the argument of any trig functions.

Part E At the position x=0, what is the displacement of the string (assuming that the standing wave ys(x,t) is present)? Part G From

Part F we know that the string is perfectly straight at time t=π2ω. Which of the following statements does the string's being straight imply about the energy stored in the strJHJMNMMUJJHTGGHing?

a.There is no energy stored in the string: The string will remain straight for all subsequent times.

b.Energy will flow into the string, causing the standing wave to form at a later time.

c.Although the string is straight at time t=π2ω, parts of the string have nonzero velocity. Therefore, there is energy stored in the string.

d.The total mechanical energy in the string oscillates but is constant if averaged over a complete cycle.

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The bridges often have expansion joints to account for the changes in size due to temperature changes. Suppose a bridge is suppo
Helga [31]

Answer:

1.33 cm

Explanation:

L = 32 m, T 1 = 0 degree C , T2 = 32 degree C

Thermal expansion coefficient of steel, α = 13 x 106-6 per degree C

Let ΔL be the increase in length.

ΔL = L x α x ΔT

ΔL = 32 x 13 x 10^-6 (32 - 0)

ΔL = 0.0133 m = 1.33 cm

6 0
3 years ago
What is the speed of a transverse wave in a rope of length 3.1 m and mass 86 g under a tension of 380 n?
stellarik [79]

The speed of a transverse wave( v) = 117.03 m/s

The formula we can use in this case would be:

v = sqrt (T / (m / l))

Where,

v = is the velocity of the transverse wave = unknown (?)

T = is the tension on the rope = 380 N

m = is the mass of the rope = 86.0 g = 0.086 kg

l = is the length of the rope = 3.1 m

Substituting the given values into the equation to search for the speed v:

v = sqrt (380 N/(0.086 kg /3.1 m))

v = sqrt (380 * 3.1/ 0.086)

v = sqrt (13,697.67)

v = 117.03 m/s

speed of a transverse wave( v) = 117.03 m/s

Learn more about  transverse wave here:

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4 0
1 year ago
How many meters are in 32 kilometers
lukranit [14]

Answer:

32,000 m

Explanation:

Conversion

1km ===> 1000m

32km===>x

x = (32 × 1000) ÷ 1

5 0
3 years ago
Computers A and B implement the same ISA. Computer A has a clock cycle time of 200 ps and an effective CPI of 1.5 for some progr
lesya692 [45]

Answer:

Computer A is 1.41 times faster than the Computer B

Explanation:

Assume that number of instruction in the program is 1

Clock time  of computer A is CT_{A} =200 ps

Clock time  of computer B is CT_{B} =250 ps

Effective CPI of computer A is CPI_{A} =1.5

Effective CPI of computer B isCPI_{B} =1.7

CPU time of A is

CPU_{time}=instructions \times CPA_{A} \times CT_{A}\\CPU_{time}=1 \times 1.5 \times 200=300 sec

CPU time of B is

CPU_{time}=instructions \times CPA_{B} \times CT_{B}\\CPU_{time}=1 \times 1.7 \times 250=425 sec

Hence Computer A is Faster by \frac{425}{300} =1.41

Computer A is 1.41 times faster than the Computer B

4 0
3 years ago
Which resistors in the circuit are connected in series?
Lisa [10]

Answer:

it's C and D... do you understand?

7 0
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