Select the correct answer.
2 answers:
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F = normal force by each board on each side
W = weight of the board in between acting in down direction = 95.5 N
f = frictional force in upward direction by each board
= coefficient of friction = 0.663
Using equilibrium of force in Upward direction
f + f = W
f = W/2
f = 95.5/2 = 47.75 N
frictional force is given as
f = F
47.75 = (0.663) F
F = 72.02 N
Answer:
<em>We need to (at least) apply a force of 9.8 N to move the block</em>
Explanation:
<u>Second Newton's Law</u>
If a net force different from zero is applied to an object of mass m, then it will move at an acceleration a, given by
If we apply a force F to an object placed on a rough surface, the only way to make it move is to beat the friction force which is given by
Where is the static friction coefficient and
is the normal force exerted by the table to the object. Since there is no motion in the vertical direction the normal force equals the weight of the object:
The friction force is
Thus, we need to (at least) apply a force of 9.8 N to move the block