Question

. A ferry is crossing a river. If the ferry is headed due north with a speed of 2.5 m/s relative to the water and the river’s velocity is 3.0 m/s to the east, what will the boat’s velocity relative to Earth be?

Answer 1

Answer:

The boat's velocity relative to Earth is 3.91 m/s.

Explanation:

Given;

speed of ferry due north, $V_y$ = 2.5 m/s

speed of the river to the east, $V_x$ = 3.0 m/s

The boat's velocity relative to Earth is given by;

$V = \sqrt{V_x^2 + V_y^2} \\\\V = \sqrt{(3)^2+(2.5)^2}\\\\V = 3.91 \ m/s$

Therefore, the boat's velocity relative to Earth is 3.91 m/s.