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The distance between two consecutive nodes and the amplitude after 0.56s are m/2 and 1.75×10^(-4) m respectively.
<h3>What's the distance between consecutive nodes of the displacement of air molecules?</h3>
- Wavelength is the distance between two consecutive nodes or toughs or crests or anti-nodes.
- So, distance between consecutive nodes = wavelength = 2π÷k
= 2π/(4π÷m)
= m/2
<h3>What's the amplitude after 0.56s of the displacement of air molecules?</h3>
Displacement after 0.56 s = 0.008×cos(50π×0.56s)
=1.75×10^(-4) m
Thus, we can conclude that the distance between consecutive nodes and displacement after 0.56 s are m/2 and 1.75×10^(-4) m respectively.
Disclaimer: The question was given incomplete on the portal. Here is the complete question.
Question: The particle displacement y of air molecules due to a sound wave is given by y=0.008coswtsinkz where k=4π÷m and w=50π rads/s.
Calculate:
I) the distance between 2 consecutive nodes
ii) the amplitude after 0.565s
Learn more about the wavelength here:
brainly.com/question/10750459
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The force acting on the cart is 1.43 N.
<h3>What is force?</h3>
Force can be defined as the product of mass and acceleration.
To calculate the force acting on the cart, we use the formula below.
Formula:
- F = m(v-u)/t................. Equation 1
Where:
- F = Force acting on the cart
- m = mass of the cart
- v = Final velocity
- u = initial velocity
- t = time
From the question,
Given:
- m = 500 g = 0.5 kg
- v = 30 m/s
- u = 10 m/s
- t = 7 seconds
Substitute these values into equation 1
- F = 0.5(30-10)/7
- F = 10/7
- F = 1.43 N.
Hence, the force acting on the cart is 1.43 N.
Learn more about force here: brainly.com/question/13370981
