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sesenic [268]
4 years ago
11

A gardener notices that some of her green plants are experiencing the

Biology
2 answers:
kozerog [31]4 years ago
5 0

Answer:

The correct answer is option A- the plants will make fewer nutrients because of chlorophyll loss.

Explanation:

Summer is experienced with high temperature and high intensity of light which shows effects on the plant.  

Exposure to high temperature and high light intensity above threshold cause several physiological and morphological changes in the plants like affect the chlorophyll. Chlorophyll gets degraded by a process called " chlorosis" due to which brown and yellow patches start appearing on the leaves.

The chlorophyll loss leads to less production of glucose molecule as the sunlight is not captured by the chlorophyll, a pre-requisite condition of the photosynthesis.

Thus, option- A is the correct option.

eduard4 years ago
3 0

Answer:

B. The plants will make fewer nutrients because of chlorophyll loss.

Explanation:

The surface of the leaf is lined with chloroplasts.

Since the leaf sizes have been reduced, chloroplasts have followed. Thus, there are less chlorophyll pigments, indicating less chances of photosynthesis, meaning fewer nutrients made.

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Chromosomal rearrangements are considered large-scale mutations. Point mutations are considered small-scale mutations, and are o
mario62 [17]

Answer:

Please find what occurs in the single nucleotide-pair substitution below

Explanation:

Single nucleotide-pair substitution is a type of point mutation as stated in this question. Point mutation is when one nucleotide base (single) is affected in the sequence. In this single nucleotide-pair substitution, ONE nucleotide base is substituted by another base.

For example, in a DNA sequence that reads: TAA GTC GGG, a mutated sequence affected by single nucleotide-pair substitution will read as follows: TAA GTC TGG. Note that in the last codon (GGG), a single nucleotide G has been replaced by another nucleotide T. Therefore, single nucleotide-pair substitution is said to have occur.

8 0
3 years ago
A class or broad-spectrum bacteriostatic antibiotics that are produced by soil organisms and inhibit protein synthesis by bindin
Anestetic [448]

A class of broad-spectrum bacteriostatic antibiotics that are produced by soil organisms and inhibit protein synthesis by binding to bacterial ribosomes is known as Chloramphenicol.

Chloramphenicol is a drug used to treat superficial eye infections such as bacterial conjunctivitis and otitis externa. It was also used to treat typhoid fever and cholera. Chloramphenicol is an antibiotic and belongs to the class of antibacterial agents that inhibit protein synthesis.

Chloramphenicol is used to treat serious infections in different parts of the body. It may also be given with other antibiotics. However, Chlorum phenicole should not be used to prevent colds, flu, other viral infections, sore throats, other mild infections, or infections.

Learn more about Chloramphenicol here: brainly.com/question/9670046

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5 0
2 years ago
. In preparation for mitosis, DNA is copied; this is called DNA ______________________.
vampirchik [111]
I believe that is is replication, but I'm not 100%
7 0
3 years ago
Read 2 more answers
Predict the likely effect on the ability of substance L to enter the cells if substance L is attached to a large protein instead
LenKa [72]

Answer:

The cell membrane is semi-permeable. It allows some molecules to enter easily inside the cell whereas some molecules are blocked from entering the cell.

Small, polar molecules and hydrophobic molecules enter easily through the cell membrane. But large molecules and ions cannot easily move inside the cell membrane.

A hydrophilic substance like the substance L mentioned in the question enters the cell membrane through the help of carrier proteins. The substance attached to the large protein might enter through active or passive diffusion but it can only enter the cell by attaching to carrier proteins.

8 0
3 years ago
Read 2 more answers
Use the following information to answer the following question.
Sonbull [250]

Answer: If this population were in equilibrium and if the sickle-cell allele is recessive, the proportion of the population susceptible to sickle-cell anemia under typical conditions should be 0.20

Explanation: Hardy-Weinberg law provides an equation to relate genotype frequencies and allele frequencies in a randomly mating population. The equation is;

p² + 2pq + q² = 1

For 2 alleles such as A and a, where

p² = homozygous dominant

q² = homozygous recessive and

2pq = heterozygous

From the question, it is said that the sickle-cell allele (SS) constitutes 20% (that is, 20/100) of the hemoglobin alleles in the human gene pool and it is also said to be the homozygous recessive allele.

Therefore, q² = 20/100 = 0.20

4 0
3 years ago
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