Answer:
Step-by-step explanation:
This question is asking us to find where sin(2x + 30) has a sin of 1. If you look at the unit circle, 90 degrees has a sin of 1. Mathematically, it will be solved like this (begin by taking the inverse sin of both sides):
![sin^{-1}[sin(2x+30)]=sin^{-1}(1)](https://tex.z-dn.net/?f=sin%5E%7B-1%7D%5Bsin%282x%2B30%29%5D%3Dsin%5E%7B-1%7D%281%29)
On the left, the inverse sin "undoes" or cancels the sin, leaving us with
2x + 30 = sin⁻¹(1)
The right side is asking us what angle has a sin of 1, which is 90. Sub that into the right side:
2x + 30 = 90 and
2x = 60 so
x = 30
You're welcome!
Answer:
I found two different solutions. Hope one of them help!
1. x = -1/3 = -0.333
2. x = 5/2 = 2.500
Step-by-step explanation:
13 ± √ 289
x = ——————
12
Can √ 289 be simplified ?
Yes! The prime factorization of 289 is
17•17
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 289 = √ 17•17 =
± 17 • √ 1 =
± 17
So now we are looking at:
x = ( 13 ± 17) / 12
Two real solutions:
x =(13+√289)/12=(13+17)/12= 2.500
or
x =(13-√289)/12=(13-17)/12= -0.333
Two solutions were found :
x = -1/3 = -0.333
x = 5/2 = 2.500
A. f(b) = 3+b
b. f(x) = (x+3)²
c. f(x) = (x+3)/(12-x)
d. f(x) = x⁵-4x+6
e. f(x) = -45
f. f(x) = x
Answer: x = 1.28 or -1.28
